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Llana [10]
3 years ago
5

Simplify 144/864 as a fraccion

Mathematics
2 answers:
Harman [31]3 years ago
7 0

Answer:

Step-by-step explanation:

Just simplify 144/864 to its simplest version.

144/864, divide numerator and denominator by 144 and you get 1/6, it's simplest form.

ycow [4]3 years ago
6 0

Answer:

The simply version is 1/6

Step-by-step explanation:

Divide each number by 144

144/144 = 1

864/144 = 6

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I should know this, but i'm really stumped, I keep getting different answers.
Feliz [49]
Z/4-8z+2(z-5)=12/4-8*12+2(12-5)=3-96+2*7=3-96+14=-79
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3 years ago
50 POINTS PLS HELP!!!
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Answer:

Do I answer these all or just one?

Step-by-step explanation:

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3 years ago
The length of Side C D is 11 inches and the length of Side C F is 11 StartRoot 3 EndRoot inches. What is the length of Side D F?
11111nata11111 [884]

Answer:

DF^2=DH^2+HF^2

DF=√DH^2+HF^2

DF=√2(DH^2) {AS IT IS A CUBE THEN ALL SIDES ARE EQUAL}

DF=√2*11^2 {ALL SIDES OF A CUBE ARE EQUAL}

DF=√2*121

DF=√242

DF=15.555

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4 0
3 years ago
Read 2 more answers
If #log_b 5 = .41#, what is #log_b 125#?
-Dominant- [34]
A:1.23

E: note that 125= 5^3 thus, log_b (125) = log_b(5^3) we can now simplify using the rule log_b(a^c) = c • log_b (a) log_b (5^3) = 3 • log_b (5) since log_b (5) = 0.41, we know that 3 • log_b (5) = 3•0.41 = 1.23

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3 0
3 years ago
Each square and figure DNE has a side length of one unit compare the area of the two figures which figure has more area how much
Zigmanuir [339]

Answer:

✅Figure E has more area

✅Figure E has 5.14 units² much more than Figure D.

Step-by-step explanation:

The logic to solving this kind of problem is to decompose and each of the figure to find out how many squares and circles are there in each figure, them calculate the area of each figure using the formula for area of square and area of a circle.

✍️Figure D:

Figure D is composed of 2 squares and 4 semicircles (2 full circles).

Since side length of 1 square = 1 unit, therefore, radius of the semi-circle/circle = 1 unit.

Area of the 2 squares = 2(s²) = 2(1²) = 2 unit²

Area of the 2 full circles = 2(πr²) = 2(3.14*1²) = 6.28 unit²

Area of Figure D = 2 + 6.28 = 8.28 unit²

✍️Figure E:

Figure E is composed of 4 squares and 6 quarter circles (3 full circles).

Area of the 4 squares = 4(s²) = 4(1²) = 4 unit²

Area of the 3 full circles = 3(πr²) = 3(3.14*1²) = 9.42 units²

Area of figure E = 4 + 9.42 = 13.42 unit²

✅Therefore, we can conclude that Figure E has more area.

✅Figure E has 5.14 unit² more area than Figure D (13.42 - 8.28 = 5.14).

8 0
3 years ago
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