Question

If #log_b 5 = .41#, what is #log_b 125#?

Answer 1

A:1.23

E: note that 125= 5^3 thus, log_b (125) = log_b(5^3) we can now simplify using the rule log_b(a^c) = c • log_b (a) log_b (5^3) = 3 • log_b (5) since log_b (5) = 0.41, we know that 3 • log_b (5) = 3•0.41 = 1.23

Glad to help :D