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3 years ago

10

The length of Side C D is 11 inches and the length of Side C F is 11 StartRoot 3 EndRoot inches. What is the length of Side D F?

Round to the nearest tenth.
11 inches
15.6 inches
19.1 inches
22 inches

2 answers:

Zigmanuir [339]3 years ago

8 0

Answer:

b

Step-by-step explanation:

11111nata11111 [884]3 years ago

4 0

Answer:

DF^2=DH^2+HF^2

DF=√DH^2+HF^2

DF=√2(DH^2) {AS IT IS A CUBE THEN ALL SIDES ARE EQUAL}

DF=√2*11^2 {ALL SIDES OF A CUBE ARE EQUAL}

DF=√2*121

DF=√242

DF=15.555

THEREFORE,OPTION B..

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Step-by-step explanation:

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3 years ago

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-1+5/4x=-16<br> What number is x representing?

ValentinkaMS [17]

Answer:

x = -12,

Step-by-step explanation:

-1 + 5/4x = -16

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4 years ago

The vertices of ∆ABC are A(-2, 2), B(6, 2), and C(0, 8). The perimeter of ∆ABC is units is? What is the area?

11111nata11111 [884]

we have

$A(-2, 2),B(6, 2),C(0, 8)$

see the attached figure to better understand the problem

we know that

The perimeter of the triangle is equal to

$P=AB+BC+AC$

and

the area of the triangle is equal to

$A=\frac{1}{2}*base *heigth$

in this problem

$base=AB\\heigth=DC$

we know that

The distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

Step $1$

<u>Find the distance AB</u>

$A(-2, 2),B(6, 2)$

Substitute the values in the formula

$d=\sqrt{(2-2)^{2}+(6+2)^{2}}$

$d=\sqrt{(0)^{2}+(8)^{2}}$

$dAB=8\ units$

Step $2$

<u>Find the distance BC</u>

$B(6, 2),C(0, 8)$

Substitute the values in the formula

$d=\sqrt{(8-2)^{2}+(0-6)^{2}}$

$d=\sqrt{(6)^{2}+(-6)^{2}}$

$dBC=6\sqrt{2}\ units$

Step $3$

<u>Find the distance AC</u>

$A(-2, 2),C(0, 8)$

Substitute the values in the formula

$d=\sqrt{(8-2)^{2}+(0+2)^{2}}$

$d=\sqrt{(6)^{2}+(2)^{2}}$

$dAC=2\sqrt{10}\ units$

Step $4$

<u>Find the distance DC</u>

$D(0, 2),C(0, 8)$

Substitute the values in the formula

$d=\sqrt{(8-2)^{2}+(0-0)^{2}}$

$d=\sqrt{(6)^{2}+(0)^{2}}$

$dDC=6\ units$

Step $5$

<u>Find the perimeter of the triangle</u>

$P=AB+BC+AC$

substitute the values

$P=8\ units+6\sqrt{2}\ units+2\sqrt{10}\ units$

$P=22.81\ units$

therefore

The perimeter of the triangle is equal to $22.81\ units$

Step $6$

<u>Find the area of the triangle</u>

$A=\frac{1}{2}*base *heigth$

in this problem

$base=AB=8\ units\\heigth=DC=6\ units$

substitute the values

$A=\frac{1}{2}*8*6$

$A=24\ units^{2}$

therefore

the area of the triangle is $24\ units^{2}$

4 0

3 years ago

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Add the integers.<br><br> 1. -2 +(-5)<br><br> 2. -2 +(-2)<br><br> 3. -13 +9

Maru [420]

-7 because when it’s +(-) it’s always the same as the outside sign
-4 same thing explained above
-4

hope this helps

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nikitadnepr [17]

The answer for question 47 is A

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3 years ago