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Step-by-step explanation:
Roland’s Boat Tours will make more money if they sell more economy seats, hence the maximum profit is attained if they only sell the minimum deluxe seat which is 6
6*35+ 24*40 = 210+960= $1170
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Given details
To make a complete tour, at least 1 economy seats
and 6 deluxe seats
Maximum passengers per tour = 30
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<em>"Boat Tours makes $40 profit for each </em><em>economy</em><em> seat sold and $35 profit for each deluxe seat sold"</em>
<em> </em>Therefore, to maximise profit, he needs to take more of economy seats
Hence
Let a deluxe seat be x and economy seat be y
Maximise
6 x+ 24y = 30
The maximum profit from one tour is = 6*35+ 24*40 = 210+960= $1170
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brainly.com/question/25828237
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To find the z-score for a weight of 196 oz., use

A table for the cumulative distribution function for the normal distribution (see picture) gives the area 0.9772 BELOW the z-score z = 2. Carl is wondering about the percentage of boxes with weights ABOVE z = 2. The total area under the normal curve is 1, so subtract .9772 from 1.0000.
1.0000 - .9772 = 0.0228, so about 2.3% of the boxes will weigh more than 196 oz.
G = 6x
to solve for x divide both sides by 6
x = g/6
A) let the number of cameras sold per day for breakeven be x
Total daily cost = 2000 + 9x
Total daily revenue = 17x
therefore for just covering expenses both cost and revenue must be equal
2000 + 9x = 17x
2000 = 17x - 9x = 8x
x = 2000/8 = 250 cameras
b) increasing production by 50 cameras per day will give a daily profit of;
50 * (17 - 9) = 50 * 8 = $400 (seeing that the fixed daily cost of $2000 remains unchanged)
It's a