Let V = the launch velocity
Let θ = the launch angle
Let d = the horizontal distance traveled
Ignore air resistance.
The horizontal component of velocity is
u = V cos θ
The time of flight is
t = d/(V cosθ) = (d/V) secθ
Create a table of θ versus t as shown below.
θ t/(d/V)
---- ----------
45 1.4142
40 1.3054
35 1.2208
30 1.1547
The graph shows that as the launch angle decreases below 45°, the time of flight decreases.
Therefore arrow b (θ < 45°) arrives first.
Answer: Arrow b arrives first.
Answer:
PQ = 4
Step-by-step explanation:
As ; PQ=QR
PR = 8
PR= PQ+QR —> 8 = 2x —> x= 8/2 = 4
SO ; PQ = 4 , QR = 4
I hope I helped you^_^
Answer:
-3/5
Step-by-step explanation:
We can find the slope using the slope formula
m= ( y2-y1)/(x2-x1)
= ( 8-5)/(-7 - -2)
= (8-5)/(-7+2)
= 3/-5
- 3/5
USE (m a t h w a y) its real easy to use
Step-by-step explanation: