so we know that 24% of the students buy their lunch at the cafeteria, and 190 students brownbag.
well, 100% - 24% = 76%, so the remainder of the students, the one that is not part of the 24% is 76%, and we know that's 190 of them.
since 190 is 76%, how much is the 24%?
![\bf \begin{array}{ccll} amount&\%\\ \cline{1-2} 190&76\\ x&24 \end{array}\implies \cfrac{190}{x}=\cfrac{76}{24}\implies 4560=76x \\\\\\ \cfrac{4560}{76}=x\implies 60=x \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{total amount of students}}{190+60\implies 250}](https://tex.z-dn.net/?f=%5Cbf%20%5Cbegin%7Barray%7D%7Bccll%7D%20amount%26%5C%25%5C%5C%20%5Ccline%7B1-2%7D%20190%2676%5C%5C%20x%2624%20%5Cend%7Barray%7D%5Cimplies%20%5Ccfrac%7B190%7D%7Bx%7D%3D%5Ccfrac%7B76%7D%7B24%7D%5Cimplies%204560%3D76x%20%5C%5C%5C%5C%5C%5C%20%5Ccfrac%7B4560%7D%7B76%7D%3Dx%5Cimplies%2060%3Dx%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Cstackrel%7B%5Ctextit%7Btotal%20amount%20of%20students%7D%7D%7B190%2B60%5Cimplies%20250%7D)
Answer:
525,000 LL
Step-by-step explanation:
6 x 3 = 18 (days)
150,000 x 3 = 450,000
21 - 18 = 3 so 6 * 2 = 3 ( 150,000 *(divide) 2 = 75,000)
so 450,000 + 75,000 = 525,000
Each hour,
x makes b/6 bearings
y makes b/4 bearings
z makes b/3 bearings
Together, each hour, x, y and z together make
b/6+b/4+b/3=b(1/6+1/4+1/3)=b(2/12+3/12+4/12)=b(3/4)=3b/4 bearings.
Time to make b bearings =
b/(3b/4)=4/3 hours = 1 hour 20 minutes.
Answer:
the triangle is right
Step-by-step explanation:
The Pythagorean theorem dictates that a^2 +b^2=c^2
6^2+8^2=10^2
36+64=100
100=100
Answer:
1/9x - y = -5
General Formulas and Concepts:
<u>Pre-Algebra</u>
<u>Algebra I</u>
Standard Form: Ax + By = C
Slope-Intercept Form: y = mx + b
Step-by-step explanation:
<u>Step 1: Define equation</u>
Slope-Intercept Form: y = 1/9x + 5
<u>Step 2: Find Standard Form</u>
- Subtract 1/9x on both sides: -1/9x + y = 5
- Multiply -1 on both sides: 1/9x - y = -5
