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Nina [5.8K]
2 years ago
15

Each side of the cube is 8cm and the mass of the cube is 1,536g. What is the density of the cube?

Mathematics
1 answer:
skad [1K]2 years ago
5 0

Answer:

The volume is 8^3 = 512 cm^3, and the mass is 1,536g. So the density is 1,536/512 = 0.003 g/cm^3. (Note that the number of significant digits should be 1, as 8 cm being the side length of the cube is in one significant digit.)

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Reduce 36/45 to lowest terms and write the numerator in the blank.
saveliy_v [14]
4/5 is your answer

Hope this helps
7 0
3 years ago
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Using the approximation 3.14 for \pi what is the radius of a circle with circumference 75.4m
Charra [1.4K]

Answer:

The radius of the circle is 12.006 m.

Step-by-step explanation:

Let us assume the radius of the circle = r

Circumference  = 75.4 m

Now, CIRCUMFERENCE OF A CIRCLE = 2 π r

⇒ 75 .4 m = 2 π r

Now, putting  π = 3.14, we get:

75 .4 m = 2 (3.14)  r

⇒ 75.4 = 6. 28 r

or, r = 75.4/6.28 =  12.006

or, r  = 12.006 m

Hence, the radius of the circle with circumference 75.4 m is 12.006 m.

3 0
3 years ago
4.) What is the exact value of sinθ when θ lies in Quadrant II and cosθ=−513
dimaraw [331]

Answer:

Part 4) sin(\theta)=\frac{12}{13}

Part 10) The angle of elevation is 40.36\°

Part 11) The angle of depression is 78.61\°

Part 12) arcsin(0.5)=30\°  or arcsin(0.5)=150\°

Part 13) -45\°  or 225\°

Step-by-step explanation:

Part 4) we have that

cos(\theta)=-\frac{5}{13}

The angle theta lies in Quadrant II

so

The sine of angle theta is positive

Remember that

sin^{2}(\theta)+ cos^{2}(\theta)=1

substitute the given value

sin^{2}(\theta)+(-\frac{5}{13})^{2}=1

sin^{2}(\theta)+(\frac{25}{169})=1

sin^{2}(\theta)=1-(\frac{25}{169})  

sin^{2}(\theta)=(\frac{144}{169})

sin(\theta)=\frac{12}{13}

Part 10)

Let

\theta ----> angle of elevation

we know that

tan(\theta)=\frac{85}{100} ----> opposite side angle theta divided by adjacent side angle theta

\theta=arctan(\frac{85}{100})=40.36\°

Part 11)

Let

\theta ----> angle of depression

we know that

sin(\theta)=\frac{5,389-2,405}{3,044} ----> opposite side angle theta divided by hypotenuse

sin(\theta)=\frac{2,984}{3,044}

\theta=arcsin(\frac{2,984}{3,044})=78.61\°

Part 12) What is the exact value of arcsin(0.5)?

Remember that

sin(30\°)=0.5

therefore

arcsin(0.5) -----> has two solutions

arcsin(0.5)=30\° ----> I Quadrant

or

arcsin(0.5)=180\°-30\°=150\° ----> II Quadrant

Part 13) What is the exact value of arcsin(-\frac{\sqrt{2}}{2})

The sine is negative

so

The angle lies in Quadrant III or Quadrant IV

Remember that

sin(45\°)=\frac{\sqrt{2}}{2}

therefore

arcsin(-\frac{\sqrt{2}}{2}) ----> has two solutions

arcsin(-\frac{\sqrt{2}}{2})=-45\° ----> IV Quadrant

or

arcsin(-\frac{\sqrt{2}}{2})=180\°+45\°=225\° ----> III Quadrant

5 0
3 years ago
Express 0.01620.01620, point, 0162 as a fraction.
just olya [345]
162/10000 is the answer to this question

8 0
3 years ago
Find the values of x and y
PSYCHO15rus [73]

Hi there!

So you're looking at an equilateral triangle, which is a big word that basically means all three sides are equal and all three angles are 60°.


Knowing that, the mesure of one side is 7, so necessarily the side "x" is also equal to 7.

So the value of x is : 7


And since all angles are of 60°, necessarily the angle "y" has an angle of 60°.

So the value of y° is : 60°


There you go! I really hope this helped, if there's anything just let me know! :)

6 0
3 years ago
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