Answer:
Choice B: .
Step-by-step explanation:
For a parabola with vertex , the vertex form equation of that parabola in would be:
.
In this question, the vertex is , such that and . There would exist a constant such that the equation of this parabola would be:
.
The next step is to find the value of the constant .
Given that this parabola includes the point , and would need to satisfy the equation of this parabola, .
Substitute these two values into the equation for this parabola:
.
Solve this equation for :
.
.
Hence, the equation of this parabola would be:
.
The dimensions that would result to maximum area will be found as follows:
let the length be x, the width will be 32-x
thus the area will be given by:
P(x)=x(32-x)=32x-x²
At maximum area:
dP'(x)=0
from the expression:
P'(x)=32-2x=0
solving for x
32=2x
x=16 inches
thus the dimensions that will result in maximum are is length=16 inches and width=16 inches
Answer:
with what
Step-by-step explanation:
tell me i think i can help
X+y=2 (label equation one)
x-y=4 (label equation two)
y=-x+2 (equation one rearranged, label this equation equation three)
sub 3 into 2
x-(-x+2)=4
x+x-2=4
2x-2=4
2x=6
x=3
sub x=3 into equation one
3+y=2
y=-1
therefore x=3 and y=-1