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Romashka [77]
3 years ago
14

If there are 32 boys and 24 girls in a room, fill out all the possible ratios of boys to girls​

Mathematics
2 answers:
Nikitich [7]3 years ago
5 0

4 boys and 3 girls.

divide 32 by 8 and 24 by 8.

You will get 4 and 3

maks197457 [2]3 years ago
3 0

Answer:

16 boys : 12 girls

8 boys : 6 girls

4 boys : 3 girls

Step-by-step explanation:

We divide each number 32 and 24 by their common factors. Which would be 2,4, and 8. So each time that we divide we could keep dividing the numbers by two to get to the finally simplyfied ratio. (32/2 =16 then 16/2 =8 finally 8/2 =4) we would also do that for 24. (24/2 = 12 then 12/2 =6 finally 6/2 =3)

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Consider the graphs of f(x) and g(x).
butalik [34]

Answer:

The value of k is -7

Step-by-step explanation:

We are given the graph of f(x) and g(x). If g(x)=f(x)+k

If we shift f(x) k unit vertical get g(x).

If k>0 then shift up

If k<0 then shift down.

f(x) and g(x) are both parabola curve.

First we find the vertex of f(x) and g(x)

Vertex of f(x) = (3,1)

Vertex of g(x) = (3,-6)

We can see change in y co-ordinate only.

f(x) shift 7 unit down to get g(x)

g(x)=f(x)-7

Therefore, The value of k is -7

5 0
3 years ago
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Suppose $1,000 is borrowed for one year at 8% simple interest. How much is due at the end of the year to
AleksAgata [21]

Answer:

you will be bankrupt simple!

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3 years ago
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12−x2y if x=−7 and y=2
Taya2010 [7]

Answer:

the answer is 16 im pretty sure

6 0
2 years ago
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X Angle 1 and Angle 2 are supplementary, Solve for x if angle 1 = 2x -3 and/3
Alona [7]

9514 1404 393

Answer:

  ∠1 = 67°; ∠2 = 113°

Step-by-step explanation:

<u>Given</u>:

  ∠1 = 2x-3

  ∠2 = 3x +8

  ∠1 +∠2 = 180

<u>Find</u>:

  ∠1, ∠2

<u>Solution</u>:

Substituting the first two relations into the third, we have ...

  (2x -3) +(3x +8) = 180

  5x +5 = 180 . . . eliminate parentheses

  x + 1 = 36 . . . . . divide by 5

  x = 35

Then the angles are ...

  ∠1 = 2x-3 = 2(35) -3

  ∠1 = 67°

  ∠2 = 3x +8 = 3(35) +8

  ∠2 = 113°

5 0
3 years ago
Anna is trying to save some money on her electric bill. Her electric company has come up with a new plan designed to charge cust
VMariaS [17]
First, we are going to calculate her monthly off-peak usage:
1,185 kWh - 500 kWh = 685 kWh

Now that we know her monthly electricity consumption is 500 kWh on-peak and 685 kWh off-peak, lets calculate the cost of each plan:
<span>Standard use plan
</span>1,185 kWh - 600 kWh = 585 kWh
- For the first 600 KWh:
 600kWh( \frac{8.5cents}{kWh} )=5100cents
Since 100 cents = 1 dollar, 5100cents( \frac{1dollar}{100cents} ) = $51
- For the remaining 585 kWh:
 585 kWh( \frac{11cents}{kWh} )=6435cents
Since 100 cents = 1 dollar, 6435cents( \frac{1dollar}{100cents}) = $64.35
Total cost of the standard use plan: $51 + $64.35 = $115.35

Interval use plan
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Since 100 cents = 1 dollar, 8000cents( \frac{1dollar}{100cents} ) = $80
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Since 100 cents = 1 dollar, 2740cents( \frac{1dollar}{100cents}) = $27.40
Total cost of the interval use plan: $80 + $27.40 = $107.40

We can conclude that:
1. The new interval plan will be better for Anna since she will save $7.95 per month in her electric bill.
2. The correct answer is: <span>b.standard use plan - $115.35; interval use plan - $107.40</span>
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3 years ago
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