Let f(x) = x² + 6x²-x+ 5 then ,
number to be added be P
then,
f(x) = x² + 6x²-x+ 5 +P
According to the qn,
(x+3) is exactly divisible by zero then,
R=0
comparing .. we get a= -3
now by remainder theorm
R=f(a)
0=f(-3)
0=(-3)² + 6(-3)²-(-3)+ 5 + P
0= 9 + 54 + 3 + 5 + P
-71=P
therefore, -71 should be added.
Hope you understand
Answer:
C. g(x) = 4x²
Step-by-step explanation:
The general equation for a parabola is
y = ax² + bx +c
Since ƒ(x) = x², a=1, b =0, c =0
For g(x), the vertex is still at the origin, so
g(x) = ax²
The graph passes through (1,4).
Insert the coordinates of the point.
4 = a(1)²
a = 4
g(x) = 4x²
The figure below shows that the graph of g(x) = 4x² passes through the point (1, 4).
The answer is 523.6 and all you have to do is round it to the nearest hundredth
Answer:
12 boys
Step-by-step explanation:
- Set up a proportion:
- Cross multiply, then divide: 3 × 16 = 48, 48 ÷ 4 = 12
I hope this helps!
The slope of the line passing through (1,-5) and (4,1) is 2