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erastovalidia [21]
2 years ago
8

Can someone please help me with math.

Mathematics
1 answer:
Goshia [24]2 years ago
8 0
I think that the correct answers are a,d,c
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8. Sven sells hamburgers at a ballpark. He earns $14.50/h, plus $0.50
Komok [63]

Answer:

Part A: $55.50

Part B: 52 hamburgers(sorry if I am wrong for part b but I think it is right)

Step-by-step explanation:

Part A:     $14.50 x 3= $43.50  +         24 x $0.50= $12=        

 ($ earned per hrs  x hrs worked)+  ($ per hamburger sold x times amount)

Hence $43.50 + $12= $55.50.

Part B:        $14.50 x 6.5 = $94.25                           $120 - $94.25= $25.75

 ($ earned per hrs  x hrs worked x x hrs worked)   ($ earned - $ earn from shif

 $25.75/0.50=51.5 (51.5 rounded to nearest burgers is 52 burgers)

Hence answer is 52 burgers.

Please rate Good and mark Brainliest

Thank You

5 0
3 years ago
It takes 27 pounds of seed to completely plant a 3-acre field. How many pounds of seed are needed per acre?
Ray Of Light [21]

Answer:

9 pounds of seed per acre.

Step-by-step explanation:

All you have to do is division.  It takes 27 pounds of seed to make 3 acres, so 27 divided by 3.  That gives you 9.

5 0
3 years ago
How would I solve this equation for mass (m)?
zaharov [31]
Simple...

you have: F= \frac{G m^{2} }{ d^{2} }

You want to find m-->>>

1.)Isolate m

d^{2} *F= \frac{G m^{2} }{ d^{2} } * d^{2}

Leaving you with...

F*d^{2}=G m^{2}

Keep isolating m-->>>

F* d^{2} =G m^{2}

\frac{F* d^{2} }{G} = \frac{G m^{2} }{G}

Square root to solve what just m is-->>>

\sqrt{ \frac{F* d^{2} }{G} } = \sqrt{ m^{2} }

=\sqrt{ \frac{F* d^{2} }{G}  } =m

That is how you solve for m...

Thus, your answer.
7 0
2 years ago
Which of the following equations has no real solutions?
kupik [55]
B. 5x - 8 = 40x - 8 has no solution because on the right side we will get 0
6 0
3 years ago
The mean life of a television set is 119 months with a standard deviation of 14 months. If a sample of 74 televisions is randoml
irina [24]

Answer:

50.34% probability that the sample mean would differ from the true mean by less than 1.1 months

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, the sample means with size n of at least 30 can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 119, \sigma = 14, n = 74, s = \frac{14}{\sqrt{74}} = 1.63

If a sample of 74 televisions is randomly selected, what is the probability that the sample mean would differ from the true mean by less than 1.1 months

This is the pvalue of Z when X = 119 + 1.1 = 120.1 subtracted by the pvalue of Z when X = 119 - 1.1 = 117.9. So

X = 120.1

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{120.1 - 119}{1.63}

Z = 0.68

Z = 0.68 has a pvalue of 0.7517

X = 117.9

Z = \frac{X - \mu}{s}

Z = \frac{117.9 - 119}{1.63}

Z = -0.68

Z = -0.68 has a pvalue of 0.2483

0.7517 - 0.2483 = 0.5034

50.34% probability that the sample mean would differ from the true mean by less than 1.1 months

8 0
2 years ago
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