Can someone please help me with math.

1 answer:

8 0

I think that the correct answers are a,d,c

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Mashcka [7]

$3x^3+7x^2-20x=0\\
x(3x^2+7x-20)=0\\
x(3x^2-5x+12x-20)=0\\
x(x(3x-5)+4(3x-5))=0\\
x(x+4)(3x-5)=0\\
x=0 \vee x=-4 \vee x=\dfrac{5}{3}$

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3 years ago

Komok [63]

1. Given

2. AD is parallel to BC

3. ∠3 ≅ ∠2

4. transitive property of congruence

5. Definition of bisect

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3 years ago

shtirl [24]

I think the answer is B

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3 years ago

alex41 [277]

This is the solution hope you can understand, i apologize for the bad handwriting

4 0

3 years ago

Shkiper50 [21]

Answer:

It is 2

Step-by-step explanation:

3 0

2 years ago