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Anvisha [2.4K]
2 years ago
12

Which of the following shows a pre-image rotated approximately 120 about point A?

Mathematics
1 answer:
Helen [10]2 years ago
8 0

Answer:

A

Step-by-step explanation:

Compare the images to 90°, which is right angle, and forms an L. A is just past 90°, B is past 270°, and C is less than 90°.

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What are all the integers for z/x33 xy/98 and 45
Ymorist [56]

Answer:

im pretty sure i got it correct inverse operations since we can say. 2 2 x x. + - = . If we start with x, then add 2 and subtract 2, ... multiplication and division, squares and square roots (for positive numbers), ... The bottom line is obviously false, and so are all of the previous lines. ... 98 x. -. -. = -. 19. 3 5 3 1 x+ - = 20. 2 3 4 7 x - + = 21. (. )3. 1. 1. 8 x-. = 22

Step-by-step explanation:

7 0
3 years ago
Katherine and Shally had $288 altogether. Katherine gave 1/3 of her share to Shally and their father gave $68 to Shally. They no
erastova [34]
1/3 of $288 is $96 So, therefore Shally had $96 at first.
But They both didn't have the same amount of money after too because:
1/3 of $288 is $96 
$96 + $68 = $164     So Shally has $164

Now, $288 - $96 = $192.    So Katherine has $192

So therefore they did not have the same amount of money but 1/3 of $288 is $96
 

4 0
3 years ago
The function for the cost of materials to make a muffin is f(x) = Three fourths x + 3, where x is the number of muffins. The fun
larisa [96]

So first let’s put g(f(x)) together by putting f(x) for every x in g(x)

We get g(f(x))=3(3/4x+3)+4 which is the selling price equation

Then you plug in 20 to find the selling price for 20 muffins.

g(f(x))=3(3/4(20)+3)+4

g(f(x))=3(60/4+3)+4

g(f(x))=3(18)+4

g(f(x))=54+4

g(f(x))=58

So the selling price will be $58 for 20 muffins.

7 0
3 years ago
Kaylib’s eye-level height is 48 ft above sea level, and addison’s eye-level height is 85 and one-third ft above sea level. how m
GalinKa [24]

The addison see to the horizon at 2 root 2mi.

We have given that,Kaylib’s eye-level height is 48 ft above sea level, and addison’s eye-level height is 85 and one-third ft above sea level.

We have to find the how much farther can addison see to the horizon

<h3>Which equation we get from the given condition?</h3>

d=\sqrt{\frac{3h}{2} }

Where, we have

d- the distance they can see in thousands

h- their eye-level height in feet

For Kaylib

d=\sqrt{\frac{3\times 48}{2} }\\\\d=\sqrt{{3(24)} }\\\\\\d=\sqrt{72}\\\\d=\sqrt{36\times 2}\\\\\\d=6\sqrt{2}....(1)

For Addison h=85(1/3)

d=\sqrt{\frac{3\times 85\frac{1}{3} }{2} }\\d\sqrt{\frac{256}{2} } \\d=\sqrt{128} \\d=8\sqrt{2} .....(2)

Subtracting both distances we get

8\sqrt{2}-6\sqrt{2}  =2\sqrt{2}

Therefore, the addison see to the horizon at 2 root 2mi.

To learn more about the eye level visit:

brainly.com/question/1392973

5 0
2 years ago
If you eat 4 medium strawberries you get 48%of your daily reccomended amount of vitiman c what fraction of your daily amount of
Nady [450]
<span>4 medium strawberries→</span><span> 48% of your daily recommend amount of vitamin c
x </span><span>medium strawberries→100% </span><span>of your daily recommend amount of vitamin c
4:48=x:100⇒48x=100*4
48x=400
x=8.33
8.33-4=4.33
4 and 1/3 of </span>medium strawberries you still need for your <span>your daily recommend amount of vitamin c.</span>
6 0
3 years ago
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