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mina [271]
2 years ago
14

PLS HELP ASAP THANKS ILL GIVE BRAINLKEST PLS THANKS PLS ASAP PLS PLS

Mathematics
2 answers:
kvv77 [185]2 years ago
8 0
PR/ML and LN/RQ
RQ/LN and LM/RP
PR/ML and MN/PQ
RQ/LN and LN/RQ
I think this is the answer
never [62]2 years ago
7 0

Answer:

LN and RQ

Step-by-step explanation:

PQR is just an enlargened version of MLN

RQ is just LN but longer

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In a school 40% are boys and 900 are girls. find the total number of students of the school and the number of boys
My name is Ann [436]

Answer:

1500 students

600 boys

Step-by-step explanation:

40% are boys, so 60% are girls.

Writing a proportion:

900 / 60% = x / 100%

x = 1500

There are 1500 students in the school, which means there are 600 boys in the school.

6 0
3 years ago
if we use a number cube with the numbers 1-6 and assign 1-4 as temperature above 80 degrees F and a 5-6 as a temperature of 80 d
Andreas93 [3]

Answer:

Keep track of every 1,2,3 or 4 rolled in 30 rolls. These represent the number of days the temperatures is above 80 degrees F. Repeat this 100 times

Step-by-step explanation:


3 0
3 years ago
Read 2 more answers
What is the value of the rational expression x/x2-9 when x = –3?
amid [387]
You're answer is D.
-3/-3(2)-9
1(2)-9
2-9
7
so it is D
3 0
3 years ago
Read 2 more answers
Please help and explain will give 40 points!
Wittaler [7]

Answer:

63.71 percent

Step-by-step explanation:

3 0
3 years ago
Find the probability that the mean annual preciptiation will be between 32 and 34 inches. variable is normally distributed
liq [111]
Supposing, for the sake of illustration, that the mean is 31.2 and the std. dev. is 1.9.

This probability can be calculated by finding z-scores and their corresponding areas under the std. normal curve.  
                                                                     34 in - 31.2 in
The area under this curve to the left of z = -------------------- = 1.47 (for 34 in)
                                                                           1.9
                                                                      32 in - 31.2 in
and that to the left of 32 in   is               z = ---------------------- = 0.421
                                                                             1.9

Know how to use a table of z-scores to find these two areas?  If not, let me know and I'll go over that with you.


My TI-83 calculator provided the following result:

normalcdf(32, 34, 31.2, 1.9) = 0.267  (answer to this sample problem)

5 0
3 years ago
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