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Answer:
200
Step-by-step explanation:
So its basically you multiply the length by the width which is 15 times 5 which is 75 then you multiply 75 times 4 which is 200 so the answer is 200.
The volume of the trough is V(w) = w³ + 20w² - 429w and the rate of change of the volume over a width of 38 inches to 53 inches is 4695 in³/in
<h3>What is an
equation?</h3>
An equation is an expression that shows the relationship between two or more variables and numbers.
Let w represent the width, hence:
length = w + 33, height = w - 13
Volume (V) = w(w + 33)(w - 13) = w³ + 20w² - 429w
V(w) = w³ + 20w² - 429w
Rate of change = dV/dw = 3w² + 40w - 429
When w = 38, dV/dw = 3(38)² + 40(38) - 429 = 5423
When w = 53, dV/dw = 3(53)² + 40(53) - 429 = 10118
Rate = 10118 - 5423 = 4695 in³/in
The volume of the trough is V(w) = w³ + 20w² - 429w and the rate of change of the volume over a width of 38 inches to 53 inches is 4695 in³/in
Find out more on equation at: brainly.com/question/2972832
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Answer:
<em>Answer is</em><em> </em><em>1345</em><em>:</em><em>12</em>
Step-by-step explanation:
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The density is 4, and the mass is 12.
So we just plug this into the equation
d = m/v
4 = 12/v
We know that the volume must be 3 to make the equation true, because 12/4 = 3.
Therefore, the answer is F. 3 cm ^3
