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enot [183]
3 years ago
7

Which of the following would be most helpful for a reflection?

Mathematics
1 answer:
Oxana [17]3 years ago
8 0
Its A- Parallel lines formed by the image…
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A chemist has 10% and 40% solutions of acid available. How many liters of each solution should be mixed to obtain 120 liters of
kaheart [24]

Answer:

100 liters of  10% solution is used and 20 liters of  40% solution is used

Step-by-step explanation:

Let "X" amount of 10% solution is used. Then the amount of 40% solution used is equal to 120-X

Now

10% of X + 40% of (120-X) = 15% of 120

On solving the above equation, we get

0.1 X + 0.4 (120-X) = 0.15 *120\\0.1 X + 48 -0.4X = 18\\0.3 X = 30\\X = 100liters

Amount of 40% solution used  = 120 -X = 120-100 = 20 liters

100 liters of  10% solution is used and 20 liters of  40% solution is used

7 0
3 years ago
For what value of a do the lines 5x–2y=3 and x+y=a intersect at a point on the y-axis?
inna [77]

Answer:

  a = -3/2

Step-by-step explanation:

You can set x=0 and solve for y to find the y-intercept in each case.

  first equation: y-intercept = -3/2

  second equation: y-intercept = a

To make these equal, we must have ...

  a = -3/2

5 0
3 years ago
The population of a pigeons in a city is 100 and is growing exponentially at 20% per year. Write a function to represent the pop
NikAS [45]

Answer:

  • p(t) = 100×1.0153^(12t)
  • 1.53% per month

Step-by-step explanation:

In general, the function will be written ...

  p(t) = (initial value)×(growth factor)^t

where t is in units comparable to those applicable to the growth factor. The growth factor is found from ...

  growth factor = 1 + growth rate

Here, the growth rate is given as 20% per year, so the growth factor per year is ...

  1 +20% = 1.20

The initial value is given as 100, so we can write the exponential function as ...

  p(t) = 100×1.20^t

__

The time period units for t are supposed to be years, but we want to find the growth rate for a month. We can do that by recognizing there are 12 months in a year. In the above equation, we can use (1/12)(12t) in place of t, then figure the growth factor (and growth rate) per month.

  p(t) = 100×(1.20^(1/12))^( 12t)

  p(t) = 100×1.0153^(12t) . . . . population exponential function

This shows the monthly growth factor is 1.0153, so the monthly rate of change (growth rate) is ...

  1.0153 -1 = 0.0153 = 1.53% . . . . monthly rate of change

5 0
3 years ago
Read 2 more answers
if you estimated your sale to be $300 but your actual sale was $345, what was your percent of the increase?
Nat2105 [25]

Answer:

The percentage change from 300 to 375 is 25 %

Step-by-step explanation:

((y2 - y1) / y1)*100 = your percentage change

(where y1=start value and y2=end value)

((375 - 300) / 300) * 100 = 25 %

8 0
3 years ago
Mary is spending money at the average rate of $5 per day. After 14 days she has $68 left. The amount left depends on the number
Radda [10]

Answer:

A. Y-68=-5(x-14)

Step-by-step explanation:

Mary is spending money at the average rate of $5 per day. After 14 days she has $68 left. The amount left depends on the number of days that have passed. write an equation for the situation

We find the equation using the point slope equation of a line. This is given as:

y - y1 = m(x-x1)

The slope intercept form will be

y = -5x + b

since the amount decreases by $5 per day...

Our slope is -5 so m=-5

We have a point (x1,y1) = (14, 68)

Hence, we have:

y-68 = -5(x-14)

Option A is correct

4 0
3 years ago
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