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Fiesta28 [93]
3 years ago
12

Use the graph below to find the coordinates of J'after J(-5, 1) was reflected over the linex=-3.

Mathematics
1 answer:
k0ka [10]3 years ago
7 0

Answer:

J's would be (-5,-4) if J was reflected over the line x=3.

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The point-slope form:

y-y_1=m(x-x_1)

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y-6=\dfrac{7}{3}(x-1)      <em>use distributive property</em>

y-6=\dfrac{7}{3}x-\dfrac{7}{3}          <em>add 6 to both sides</em>

y=\dfrac{7}{3}x+\dfrac{11}{3}        <em>multiply both sides by 3</em>

3y=7x+11           <em>subtract 7x from both sides</em>

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Answer:

point-slope form: y-6=\dfrac{7}{3}(x-1)

slope-intercept form: y=\dfrac{7}{3}x+\dfrac{11}{3}

standard form: 7x-3y=-11

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