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2 years ago

PLEASE HELP! I will give you the brainiest and A LOT of points! (Ch.5.7)

Mathematics

1 answer:

iren2701 [21]2 years ago

6 0

Answer:

company A pays more, by the end of yr 10 they pay $9000 more

Step-by-step explanation:

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How many solutions can be found for the equation 4z + 2(z - 4) = 3z + 11

Gnom [1K]

4z+2(z-4)=3z+11 perform indicated multiplication on left side

4z+2z-8=3z+11 combine like terms on left side

6z/-8=3z+11 add 8 to both sides

6z=3z+19 subtract 3z from both sides

3z=19 divide both sides by 3

z=19/3

z=6 1/3

So there is only one solution when z=6 1/3

4 0

3 years ago

Read 2 more answers

A clothing store has the sign shown in the shop window.

kicyunya [14]

Pani would pay $59 if she gets a discount of $3 on each shirt and $3 on each jeans

Step-by-step explanation:

Given

Price of shirt = $12

Price of jeans = $19

Price of shirt after $3 discount = 12-3 = $9

Price of jeans after 3 discount = 19-3 = $16

The total money Pani has to pay will be:

$9(3)+16(2)\\=27+32\\=\$59$

Pani would pay $59 if she gets a discount of $3 on each shirt and $3 on each jeans

Keywords: Discount, percent

Learn more about discount at:

#LearnwithBrainly

8 0

3 years ago

I need help finding the area

aniked [119]

<h3>Given :</h3>

Base of triangle = 7 yd
Height of triangle = 10 yd

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Area of triangle

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We know:-

When base and height of triangle is given we use this formula:

$\bigstar \boxed{ \rm Area \: of \: triangle = \frac{base \times height}{2} }$

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So:-

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$\dashrightarrow \sf \: Area \: of \: triangle = \dfrac{base \times height}{2} \\$

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$\dashrightarrow \sf \: Area \: of \: triangle = \dfrac{7 \times 10}{2} \\$

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$\dashrightarrow \sf \: Area \: of \: triangle = \dfrac{7 \times 5 \times2 }{2} \\$

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$\dashrightarrow \sf \: Area \: of \: triangle = \dfrac{7 \times 5 \times\cancel2 }{\cancel2} \\$

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$\dashrightarrow \sf \: Area \: of \: triangle = \dfrac{7 \times 5 \times1 }{1} \\$

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$\dashrightarrow \sf \: Area \: of \: triangle =7 \times 5$

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$\dashrightarrow \bf \: Area \: of \: triangle =35 {yd}^{2} \\$

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$\therefore \underline{\textsf{ \textbf {\: Area \: of \: triangle = \red{35}}} { \red{\bf{yd} }^{ \red2} }}$

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$\small\begin{gathered}\begin{gathered}\begin{gathered}\boxed{\begin {array}{cc}\\ \dag\quad \Large\underline{\bf \small{Formulas\:of\:Areas:-}}\\ \\ \star\sf Square=(side)^2\\ \\ \star\sf Rectangle=Length\times Breadth \\\\ \star\sf Triangle=\dfrac{1}{2}\times Base\times Height \\\\ \star \sf Scalene\triangle=\sqrt {s (s-a)(s-b)(s-c)}\\ \\ \star \sf Rhombus =\dfrac {1}{2}\times d_1\times d_2 \\\\ \star\sf Rhombus =\:\dfrac {1}{2}d\sqrt {4a^2-d^2}\\ \\ \star\sf Parallelogram =Base\times Height\\\\ \star\sf Trapezium =\dfrac {1}{2}(a+b)\times Height \\ \\ \star\sf Equilateral\:Triangle=\dfrac {\sqrt{3}}{4}(side)^2\end {array}}\end{gathered}\end{gathered}\end{gathered}$ ]