My guess is that you're doing the Law of Cosines? You have everything you need for that except the angle theta, which is the thing you need to find. It's set up like this: (8)^2 = (10)^2 + (5)^2 -[2(10)(5)cos A] I used A instead of theta. Doing that math, you have: 64 = 100 + 25 -[ 100 cos A]; 64 = 125 - 100 cos A;
-61 = - 100 cos A; -61 / -100 = cos A; .61 = cos A. Now use your inverse function on your calculator to find cos^-1(.61) and that equals 52.4
E. II or IV only because it will have different signs if point Q was in either of those quadrants
Given:
The point is (6,2).
To find:
The image of given point after rotation of 270 degrees.
Solution:
Let the given point be P(6,2).
Rotation of 270 degrees means the figure is rotated 270 degrees counterclockwise about the origin. So, the rule of rotation is
Using this rule, we get
Therefore, the image of given point is (2,-6).
Answer:
x = -48
Step-by-step explanation:
4x + 2 = 5(x + 10)
expand the 5(x+10)
4x + 2 = 5x + 50
-2 both sides
4x + 2 - 2 = 5x + 50 - 2
simplify
4x = 5x + 48
-5x both sides
4x - 5x = 5x + 48 - 5x
simplify
-x = 48
÷ (-1) both sides
-x ÷ (-1) = 48 ÷ (-1)
simplify
x = -48
The answer is x = -48.
Answer: 81
Step-by-step explanation:
Mean of four nos = 85
Score = 85 x 4 = 340
Deduct 97 from 340 = 243
Mean of three nos. 243/3 = 81
