Irrational is the correct answer
Both a rhombus and a rectangle have diagonals that are perpendicular bisectors, but the ones formed in a square are all congruent, so that is probably the most descriptive one.
Answer: if Gregory draws the segment with endpoints A and A’, then the midpoint will lie on the line of reflection.
Explanation:
Given that a triangle ABC is reflected in triangle A'B'C'
Here reflection is done on a line
If you imagine the line as a mirror then ABC will have image on the mirror line as A'B'C'
Recall that in a mirror the object and image would be equidistant from the mirror and also the line joining the image and object would be perpendicular to the mirror
But note that corresponding images will only be perpendicular bisector to the line
So A and A' only will be corresponding so AA' will have mid point on line
Option 1 is right
Answer:
Step-by-step explanation:
We can even break this down further by simply only looking at the total amount of males, and finding the proportion of males that are divorced, which is 
, the same value.
Note that P(Male | Divorced) means the probability of choosing a male, given (|) that person is divorced.
The slope of <em>y</em> = 2<em>x</em> - 5 is 2. Parallel lines have the same slope, so the slope of the line through the given points <em>A</em> and <em>B</em> is also 2. This means
(8 - 4) / (6 - <em>n</em>) = 2
Solve for <em>n</em> :
4 / (6 - <em>n</em>) = 2
4/2 = 6 - <em>n</em>
2 = 6 - <em>n</em>
<em>n</em> = 6 - 2
<em>n</em> = 4
