All categories

3 years ago

Tom and Jim have a total of 57 fish. Tom has 16 goldfish and 5

Mathematics

2 answers:

ICE Princess25 [194]3 years ago

8 0

Answer: 12

Step-by-step explanation:

Tom's fish

goldfish=16

betta fish=5

total tom's fish=21

Jim's fish

goldfish=16+8=24

21+24=45

57-45=12

so jim has 12 betta fishs

MatroZZZ [7]3 years ago

3 0

Answer:

total = 57

all together Tom has 21 fish

if Jim has 8 more that makes it 24 gold fish for himself

21+24=45 / blank betta fish for Jim

57-45= 12 betta fish

am I correct?

You might be interested in

Enter the equation in slope-intercept form. Then graph the line described by the equation. -4x - 3y = 9

Alexus [3.1K]

Answer:

Step-by-step explanation:

-3y = 4x +9

y= -3/4x -3

5 0

3 years ago

Please help!! circles combos are too hard

malfutka [58]

Answer:

56 + 53pi

Step-by-step explanation:

Area of small circles:

diameter of small circle: 4cm

forumla to find area of circle: A = pir^2

r is radius = half of diameter -> d/2 = 4 / 2 = 2cm

A = pi (2cm)^2

A = pi (4cm)

A = 4pi

Area of large circle:

diameter of small circle: 4cm

forumla to find area of circle: A = pir^2

r is radius = half of diameter -> d/2 = 14 / 2 = 7cm

A = pi (7cm)^2

A = pi (49cm)

A = 49pi

Area of rectangle:

Area = width x length

Area = 14cm x 4cm

Area = 56cm

Add all three areas:

Area of rectangle + large circle + small circle

56cm + 49pi + 4pi = 56cm + 53pi

7 0

2 years ago

What is 254−−√+524−−√ in simplified radical form? Enter your answer in the box.

Vesna [10]

Answer:

Step-by-step explanation:

2√54+5√24

2 * sqrt(9*6) + 5*sqrt(4*6)

2*sqrt(9) *sqrt(6) + 5*sqrt(4) * sqrt(6)

2*3 sqrt(6) + 5*2 sqrt(6)

6sqrt(6)+10sqrt(6)

16sqrt(6)

8 0

3 years ago

Read 2 more answers

A pie is 3/4 and 2/3 of the pie is eaten what is left

Sidana [21]

Answer:
1/12 is left

Step by step explanation:
Find the common denominator which is 12 then you would get 9/12 (Originally 3/4) and 8/12 (Originally 2/3) and then you subtract which gets you 1/12

4 0

3 years ago

Find the laplace transform of f(t) = cosh kt = (e kt + e −kt)/2

iren2701 [21]

Hello there, hope I can help!

I assume you mean $L\left\{\frac{ekt+e-kt}{2}\right\}$
With that, let's begin

$\frac{ekt+e-kt}{2}=\frac{ekt}{2}+\frac{e}{2}-\frac{kt}{2} \ \textgreater \ L\left\{\frac{ekt}{2}-\frac{kt}{2}+\frac{e}{2}\right\}$

$\mathrm{Use\:the\:linearity\:property\:of\:Laplace\:Transform}$
$\mathrm{For\:functions\:}f\left(t\right),\:g\left(t\right)\mathrm{\:and\:constants\:}a,\:b$
$L\left\{a\cdot f\left(t\right)+b\cdot g\left(t\right)\right\}=a\cdot L\left\{f\left(t\right)\right\}+b\cdot L\left\{g\left(t\right)\right\}$
$\frac{ek}{2}L\left\{t\right\}+L\left\{\frac{e}{2}\right\}-\frac{k}{2}L\left\{t\right\}$

$L\left\{t\right\} \ \textgreater \ \mathrm{Use\:Laplace\:Transform\:table}: \:L\left\{t\right\}=\frac{1}{s^2} \ \textgreater \ L\left\{t\right\}=\frac{1}{s^2}$

$L\left\{\frac{e}{2}\right\} \ \textgreater \ \mathrm{Use\:Laplace\:Transform\:table}: \:L\left\{a\right\}=\frac{a}{s} \ \textgreater \ L\left\{\frac{e}{2}\right\}=\frac{\frac{e}{2}}{s} \ \textgreater \ \frac{e}{2s}$

$\frac{ek}{2}\cdot \frac{1}{s^2}+\frac{e}{2s}-\frac{k}{2}\cdot \frac{1}{s^2}$

$\frac{ek}{2}\cdot \frac{1}{s^2} \ \textgreater \ \mathrm{Multiply\:fractions}: \frac{a}{b}\cdot \frac{c}{d}=\frac{a\:\cdot \:c}{b\:\cdot \:d} \ \textgreater \ \frac{ek\cdot \:1}{2s^2} \ \textgreater \ \mathrm{Apply\:rule}\:1\cdot \:a=a$
$\frac{ek}{2s^2}$

$\frac{k}{2}\cdot \frac{1}{s^2} \ \textgreater \ \mathrm{Multiply\:fractions}: \frac{a}{b}\cdot \frac{c}{d}=\frac{a\:\cdot \:c}{b\:\cdot \:d} \ \textgreater \ \frac{k\cdot \:1}{2s^2} \ \textgreater \ \mathrm{Apply\:rule}\:1\cdot \:a=a$
$\frac{k}{2s^2}$

$\frac{ek}{2s^2}+\frac{e}{2s}-\frac{k}{2s^2}$

Hope this helps!

3 0

4 years ago