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Andreyy89
2 years ago
5

If x2 = 30, what is the value of x?

Mathematics
2 answers:
hammer [34]2 years ago
8 0

Answer:

15

Step-by-step explanation:

15 x 2 = 30

Mashutka [201]2 years ago
7 0
15 because 30/2 equals 15
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Please show the working and answer. you can take a picture for the working.
baherus [9]

Answer:

(a) The area of the triangle is approximately 39.0223 cm²

(b) ∠SQR is approximately 55.582°

Step-by-step explanation:

(a) By sin rule, we have;

SQ/(sin(∠SPQ)) = PQ/(sin(∠PSQ)), which gives;

5.4/(sin(52°)) = 6.8/(sin(∠PSQ))

∴ (sin(∠PSQ)) = (6.8/5.4) × (sin(52°)) ≈ 0.9923

∠PSQ = sin⁻¹(0.9923) ≈ 82.88976°

Similarly, we have;

5.4/(sin(52°)) = SP/(sin(180 - 52 - 82.88976))

Where, 180 - 52 - 82.88976 = ∠PQS = 45.11024

SP = 5.4/(sin(52°))×(sin(180 - 52 - 82.88976)) ≈ 4.8549

Given that RS : SP = 2 : 1, we have;

RS = 2 × SP = 2 × 4.8549 ≈ 9.7098

We have by cosine rule, \overline {RQ}² =  \overline {SQ}² +  \overline {SR}² - 2 × \overline {SQ} × \overline {SR} × cos(∠QSR)

∠QSR and ∠PSQ are supplementary angles, therefore;

∠QSR = 180° - ∠PSQ = 180° - 82.88976° = 97.11024°

∠QSR = 97.11024°

Therefore;

\overline {RQ}² =  5.4² +  9.7098² - 2 ×  5.4×9.7098× cos(97.11024)

\overline {RQ}² ≈ 136.42

\overline {RQ} = √(136.42) ≈ 11.6799

The area of the triangle = 1/2 ×\overline {PQ} × \overline {PR} × sin(∠SPQ)

By substituting the values, we have;

1/2 ×\overline {PQ} × \overline {PR} × sin(∠SPQ)

1/2 × 6.8 × (4.8549 + 9.7098) × sin(52°) ≈ 39.0223 cm²

The area of the triangle ≈ 39.0223 cm²

(b) By sin rule, we have;

\overline {RS}/(sin(∠SQR)) = \overline {RQ}/(sin(∠QSR))

By substituting, we have;

9.7098/(sin(∠SQR)) = 11.6799/(sin(97.11024))

sin(∠SQR) = 9.7098/(11.6799/(sin(97.11024))) ≈ 0.82493

∠SQR = sin⁻¹(0.82493) ≈ 55.582°.

8 0
3 years ago
WILL GIVE BRAINLIEST IF DO QUICKLY!!!!!: Let f(x) = 2/x and g(x) = x − 3. Write an expression for f(g(x))
givi [52]

Answer:

I dont know sorry

Step-by-step explanation:

sorrrrrrry

4 0
3 years ago
Which of the following is the correct classification of ∆mnp if m<m=35° and m<p=47°?​
AnnZ [28]

Answer:

D. Obtuse.

Step-by-step explanation:

We are told that in \Delta MNP m\angle M=35^o and m\angle P=47^o. We are asked to classify our given \Delta MNP.

We can see that angle M and angle P are acute angles as their measure is less than 90 degrees.

Let us find the measure of angle P using angle sum property of triangles, which states that sum of interior angles of a triangle is 180 degrees.

So we can set an equation as:

m\angle M+m\angle P+m\angle N=180^o

Upon substituting our given values we will get,

35^o+47^o+m\angle N=180^o

82^o+m\angle N=180^o

82^o-82^o+m\angle N=180^o-82^o

m\angle N=98^o

As measure of angle N is 98 degrees, so angle N is an obtuse angle.

Since a triangle having an angle that measures more than 90 degrees is called an obtuse triangle, therefore, \Delta MNP is an obtuse triangle and option D is the correct choice.

4 0
3 years ago
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(Help? Its a True or False Question) The following is the correct way to show the product for 0.453 × 8.1:
BigorU [14]

What is the relationship between RR' and SS'?


8 0
3 years ago
Please help me asap
Sonja [21]

Step-by-step explanation:

4/sin45=

4 \sqrt{2}

6 0
3 years ago
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