Twice the difference of a number and seven is equal to three times the sum of the number and seven

Zach divides 6 cups of fruit juice equally among 8 friends how much fruit juice does each friend get

Allisa [31]

8friends→6cups
1friend→6/8=3/4cup

7 0

3 years ago

Read 2 more answers

Graph f(x)=−3/4x−4 . Use the line tool and select two points to graph the line.

lions [1.4K]

Answer:

Two points on the line would be (0, -4) and (4, -7)

Step-by-step explanation:

In order to find this, we can start at the y-intercept. The y-intercept is the constant at the end of the equation. In this case it is -4, which gives us the first point of (0, -4).

We can find the second point by using the numerator of the slope to determine how much we go up or down (-3) and the denominator for how much we go left to right (4). So we add the 4 to the x value and add the -3 to the y value.

(4, -7)

3 0

3 years ago

WILL GIVE BRAINLIEST

grandymaker [24]

Answer:

B the service fee for coming to look at the machine

Step-by-step explanation:

4 0

3 years ago

HELP ASAP PLZZZZ

Tcecarenko [31]

QUESTION 1

The given system of equations is

$3d - e = 7...eqn(1)$
$d + e = 5...eqn(2)$

To solve by linear combination, we add equation (1) to equation (2) to get,

$3d + d= 7 + 5$

$4d = 12$

We divide through by 4 to obtain,

$d = \frac{12}{4}$

$d = 3$

We put d=3 into equation (2) to get,

$3+ e = 5$

$e = 5 - 3$

$e = 2$

$\boxed {The \: solution \: is \: (3, 2)}$

QUESTION 2

The given system is

4x + y = 5 ...eqn(1)

3x + y = 3 ...eqn(2)

To solve by linear combination, we subtract equation (2) from equation (1) to eliminate y from the equation.

This will give us,

$4x - 3x = 5 - 3$

This implies that,

$x = 2$

Put x=3 into equation (1) to get,

$4(2) + y = 5$

$8+ y = 5$

$y = 5 - 8$

$y = - 3$

The solution is

$(2,-3)$

QUESTION 3

We want to solve the system;

a – 2b = –2 ....eqn(1)

2a + 2b = 14...eqn(2)

by linear combination.

We need to add equation (1) to equation (2) to eliminate b.

This implies that,

$2a + a = 14 + - 2$

Simplify,

$3a = 12$

Divide both sides by 3 to get,

$a = 4$
Put a=4 into equation (2) to obtain,

$2(4) + 2b = 14$

$8 + 2b = 14$
$2b = 14 - 8$

$2b = 6$

$b = 3$

The ordered pair in the form (a, b) is

$(4,3)$

QUESTION 4

The given system of equations is

11x + 4y = 18 ...eqn(1)

3x + 4y = 2 ...eqn(2)

We subtract equation (2) from equation (1) to get,

$11x - 3x = 18 - 2$

$8x = 16$

$x = 2$

Put x=2 into equation (2) to obtain,

$3(2) + 4y = 2$

This implies that,

$6 + 4y = 2$

$4y = 2 - 6$

$4y = - 4$

$y=-1$

The correct answer is (2,-1).

QUESTION 5

The given system is ;

2d + e = 8...eqn1

d – e = 4...eqn2

We add the two equations to eliminate e.

This implies that,

$2d + d = 8 + 4$

$3d = 12$

We divide both sides by 3 to get,

$d = 4$

We put d=4 into equation (2) to get,

$4 - e = 4$

$- e = 4 - 4$

$- e = 0$

$e = 0$

The solution is

$(4,0)$

7 0

3 years ago

Your friend claims that if a line has a slope less than 1, then any line perpendicular to it must have a positive slope. Is your

mezya [45]

Answer:

The friend's claim is not correct

Step-by-step explanation:

we know that

If two lines are perpendicular, then their slopes are opposite reciprocal (the product of their slopes is equal yo -1)

Example

A given line has a slope of $m_1=1/2$ ---> (is less than 1)