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Rom4ik [11]
2 years ago
7

The number e is the base of the?

Mathematics
1 answer:
Vikki [24]2 years ago
5 0

Answer:

4

Step-by-step explanation:

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A $3,500 loan, taken now, with a simple interest rate of 5% per year, will require a total repayment of $3,850. At what time t w
Alecsey [184]

Answer:

Roughly 2 years

Step-by-step explanation:

3500(1.05)^t=3850

(1.05)^t=1.1

t=1.953

So roughly 2 years

5 0
3 years ago
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Which of the following expressions is equal to 5^6/5^2? A) 5 • 5 • 5 • 5 B) 5 • 5 • 5 C) 1/5•5•5•5 D) 3
lana66690 [7]

Step-by-step explanation: To simplify, we will apply the <em>Quotient Rule</em>.

The 5's in this problem are bases so as you apply the quotient rule,

subtract the exponents but leave the base alone to get 5⁴.

We can also write 5⁴ as 5 · 5 · 5 · 5.

6 0
3 years ago
1 1/4 divided by 2/3
Ksju [112]

Answer:

1.875

Step-by-step explanation:

4 0
3 years ago
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What is the equation of the circle graphed below? Use the caret ( ^ ) to enter any exponents; for example, write x2 as x^2.
kvv77 [185]
Equation of a circle in standard form:
(x-h)²+(y-k)²=r²
r=radius
(h,k) is the center.

In this case:
(h,k) =(0,0)   (h=0,k=0 )
r=4

Therefore:
(x-0)²+(y-0)²=4²
x²+y²=16

Answer: x²+y²=16
3 0
3 years ago
Which of the following is an extraneous solution of (45-3x)^1/2=x-9?
Iteru [2.4K]

Answer:

C. x =3

Step-by-step explanation:

Extraneous solution is that root of a transformed equation that doesn't satisfy the equation in it's original form because it was excluded from the domain of the original equation.

Let's solve the equation first

\sqrt{45-3x} = x-9\\Taking\ square\ on\ both\ sides\\{(\sqrt{45-3x})}^2 = {(x-9)}^2\\45-3x = x^2-18x+81\\0 = x^2-18x+81-45+3x\\x^2-15x+36 = 0\\x^2-12x-3x+36 = 0\\x(x-12)-3(x-12) = 0\\(x-3)(x-12)\\x-3 = 0\\=> x =3\\x-12 = 0\\x = 12\\We\ will\ check\ the\ solutions\ one\ by\ one\\So,\\for\ x=3\\\sqrt{45-3(3)} = 3-9\\\sqrt{45-9} = -6\\\sqrt{36}= -6\\6\neq -6\\For x=12\\\sqrt{45-3(12)} = 12-9\\\sqrt{45-36} = 6\\\sqrt{36}= 6\\6=6

Hence, we can conclude that x=3 is an extraneous solution of the equation ..

3 0
4 years ago
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