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Lilit [14]
2 years ago
10

Can y’all help me on a question 15?!

Mathematics
2 answers:
amid [387]2 years ago
6 0
I think it would be D
timofeeve [1]2 years ago
4 0

Answer:

<h2>15:</h2>

=> To Find:

=><em><u>Two </u></em><em><u>to </u></em><em><u>the </u></em><em><u>fifth </u></em><em><u>power </u></em><em><u>plus </u></em><em><u>seven </u></em><em><u>squared</u></em>

<em><u>=</u></em><em><u>></u></em><em><u> </u></em><em><u>-</u></em><em><u>-</u></em><em><u>-</u></em><em><u>-</u></em><em><u>-</u></em><em><u>-</u></em><em><u>-</u></em><em><u>-</u></em><em><u>-</u></em><em><u>-</u></em><em><u>-</u></em><em><u>-</u></em><em><u>-</u></em><em><u>-</u></em><em><u>-</u></em><em><u>-</u></em><em><u>-</u></em><em><u>-</u></em><em><u>-</u></em><em><u>-</u></em><em><u>-</u></em><em><u>-</u></em><em><u>-</u></em><em><u>-</u></em><em><u>-</u></em><em><u>-</u></em><em><u>-</u></em><em><u>-</u></em><em><u>-</u></em><em><u>-</u></em><em><u>-</u></em><em><u>-</u></em><em><u>-</u></em>

<em><u>=</u></em><em><u>></u></em><em><u> </u></em><em><u>2</u></em><em><u>⁵</u></em>

<em><u>=</u></em><em><u>></u></em><em><u> </u></em><em><u>-</u></em><em><u>-</u></em><em><u>-</u></em><em><u>-</u></em><em><u>-</u></em><em><u>-</u></em><em><u>-</u></em><em><u>-</u></em><em><u>-</u></em><em><u>-</u></em><em><u>-</u></em><em><u>-</u></em><em><u>-</u></em><em><u>-</u></em><em><u>-</u></em><em><u>-</u></em><em><u>-</u></em><em><u>-</u></em><em><u>-</u></em><em><u>-</u></em><em><u>-</u></em><em><u>-</u></em><em><u>-</u></em><em><u>-</u></em><em><u>-</u></em><em><u>-</u></em><em><u>-</u></em><em><u>-</u></em><em><u>-</u></em><em><u>-</u></em><em><u>-</u></em><em><u>-</u></em><em><u>-</u></em><em><u>-</u></em><em><u>-</u></em><em><u>-</u></em><em><u>-</u></em><em><u>-</u></em><em><u>-</u></em><em><u>-</u></em>

<em><u>=</u></em><em><u>></u></em><em><u> </u></em><em><u>2</u></em><em><u>⁵</u></em><em><u> </u></em><em><u>+</u></em><em><u> </u></em>

<em><u>=</u></em><em><u>></u></em><em><u> </u></em><em><u>-</u></em><em><u>-</u></em><em><u>-</u></em><em><u>-</u></em><em><u>-</u></em><em><u>-</u></em><em><u>-</u></em><em><u>-</u></em><em><u>-</u></em><em><u>-</u></em><em><u>-</u></em><em><u>-</u></em><em><u>-</u></em><em><u>-</u></em><em><u>-</u></em><em><u>-</u></em><em><u>-</u></em><em><u>-</u></em><em><u>-</u></em><em><u>-</u></em><em><u>-</u></em><em><u>-</u></em><em><u>-</u></em><em><u>-</u></em><em><u>-</u></em><em><u>-</u></em><em><u>-</u></em><em><u>-</u></em><em><u>-</u></em><em><u>-</u></em><em><u>-</u></em><em><u>-</u></em><em><u>-</u></em><em><u>-</u></em><em><u>-</u></em><em><u>-</u></em><em><u>-</u></em><em><u>-</u></em><em><u>-</u></em><em><u>-</u></em><em><u>-</u></em><em><u>-</u></em><em><u>-</u></em><em><u>-</u></em><em><u>-</u></em><em><u>-</u></em><em><u>-</u></em><em><u>-</u></em><em><u>-</u></em><em><u>-</u></em><em><u>-</u></em><em><u>-</u></em><em><u>-</u></em><em><u>-</u></em><em><u>-</u></em><em><u>-</u></em><em><u>-</u></em><em><u>-</u></em><em><u>-</u></em><em><u>-</u></em><em><u>-</u></em><em><u>-</u></em><em><u>-</u></em><em><u>-</u></em><em><u>-</u></em>

<em><u>=</u></em><em><u>></u></em><em><u> </u></em><em><u>2</u></em><em><u>⁵</u></em><em><u> </u></em><em><u>+</u></em><em><u> </u></em><em><u>7</u></em><em><u>²</u></em>

<em><u>Hence,</u></em><em><u> </u></em><em><u>2⁵ + 7²</u></em><em><u> </u></em><em><u>is </u></em><em><u>the</u></em><em><u> answer</u></em>

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The sum of two consecutive even integers is 66. Find the numbers.
evablogger [386]
Let the consecutive even numbers be n and n+2.
From given condition, 
n + n+2 = 66
2n = 64
∴ n = 32.
Therefore, the two consecutive even numbers are.
n = 32 and n+2 = 34.
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Suppose that the derivable functions x=x(t) and y=y(t) satisfy xcosy=2.
ololo11 [35]

Applying implicit differentiation, it is found that dy/dt when y=π/4 is of:

a-) -√2 / 2.

<h3>What is implicit differentiation?</h3>

Implicit differentiation is when we find the derivative of a function relative to a variable that is not in the definition of the function.

In this problem, the function is:

xcos(y) = 2.

The derivative is relative to t, applying the product rule, as follows:

\cos{y}\frac{dx}{dt} - x\sin{y}\frac{dy}{dt} = 0

\frac{dy}{dt} = \frac{\cos{y}\frac{dx}{dt}}{x\sin{y}}

Since dx/dt=−2, we have that:

\frac{dy}{dt} = -2\frac{\cos{y}}{x\sin{y}}

When y = π/4, x is given by:

xcos(y) = 2.

x = \frac{2}{\cos{\frac{\pi}{4}}} = \frac{2}{\frac{\sqrt{2}}{2}} = \frac{4}{\sqrt{2}} \times \frac{\sqrt{2}}{\sqrt{2}} = 2\sqrt{2}

Hence:

\frac{dy}{dt} = -2\frac{\cos{y}}{x\sin{y}}

\frac{dy}{dt} = -\frac{1}{\sqrt{2}}\cot{y}

Since cot(pi/4) = 1, we have that:

\frac{dy}{dt} = -\frac{1}{\sqrt{2}} \times \frac{\sqrt{2}}{\sqrt{2}} = -\frac{\sqrt{2}}{2}

Which means that option a is correct.

More can be learned about implicit differentiation at brainly.com/question/25608353

#SPJ1

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Answer:

The first piece is 19 inches, the second is 52, and the third piece is 57.

Step-by-step explanation:

Solve for x using (x) + (x + 33) + (3x) = 128.

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