Answer:
Part 1) m∠EOD=20°
Part 2) m∠AOD=80°
Step-by-step explanation:
Part 1) Find the measure of angle EOD
we know that °
m∠EOD=m∠EOX-m∠DOX
we have
Observing the figure
m∠EOX=140°
m∠DOX=120°
substitute
m∠EOD=140°-120°=20°
Part 2) Find the measure of angle AOD
we know that °
m∠AOD=m∠DOX-m∠AOX
we have
Observing the figure
m∠AOX=40°
m∠DOX=120°
substitute
m∠AOD=120°-40°=80°
Answer:
49N
Step-by-step explanation:
Step one
Given
When the force of 63 N acts on a certain object
the acceleration of the object is 9/ms^2
Firstly, we need to calculate the mass m
F=ma-------1
m= F/a
m= 63/9
m= 7kg
Step two:
Also, if the acceleration of the object becomes 7 m/s^2
then the force
Note: the mass remains the same= 7kg
F=ma
F=7*7
F= 49N
Answer:
In one second it turns 200 / 60 = 3 1/3 revolutions. Since one revolution is 360°, the answer is 6 2/3 π radians.
I believe it would be the second option....