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Nata [24]
2 years ago
13

AC with B between A and C,AC=12inch and AB 7in what is the ratio of AB to BC

Mathematics
1 answer:
s344n2d4d5 [400]2 years ago
7 0

Answer:

Step-by-step explanation:

AC = AB + BC;      BC = AC - AB

AC = 12 in

AB = 7 in

BC = 12 - 7

BC = 5

AB/BC = 7/5

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Factor completely 10x3+2x2+5x+1
antoniya [11.8K]
Hello,

10x^3+2x^2+5x+1\\
=10x^3+5x+2x^2+1\\
=5x(2x^2+1)+1(2x^2+1)\\
=(2x^2+1)(5x+1)

7 0
3 years ago
Read 2 more answers
The owner of a football team claims that the average attendance at games is over 523, and he is therefore justified in moving th
USPshnik [31]

Answer:

C) There is not sufficient evidence to support the claim that the mean attendance is greater than 523.

Step-by-step explanation:

Let μ be the the average attendance at games of the football team

The claim: the average attendance at games is over 523

Null and alternative hypotheses are:

  • H_{0}: μ=523
  • H_{a}: μ>523

The conclusion is failure to reject the null hypothesis.

This means that <em>test statistic</em> is lower than <em>critical value</em>.  Therefore it is not significant, there is no significant evidence to accept the <em>alternative</em> hypothesis.

That is no significant evidence that the average attendance at games of the football team is greater than 523.

7 0
2 years ago
4. Elliott deposits $500 into a savings account
Len [333]

Interest = 500 x .03 x 4

I = 60

Closing Balance = 500 (p) + 60 (1)

Closing Balance = 560

7 0
3 years ago
What is the probability of rolling a four then a three
spayn [35]

Answer:

\frac{1}{36}

Step-by-step explanation:

Total possibilities when we a roll a die at a time are 6

given we should have four for first time and then three

let us assume we rolled the dice we may get 1,2,3,4,5,6(any of these) the probability to get 4 is

PROBABILITY=\frac{\textrm{FAVOURABLE CHANCES}}{\textrm{TOTAL CHANCES}}

Favourable chances=1

Total chances=6

Probability=\frac{1}{6}

the prabability to get 4 in first roll is \frac{1}{6}.

let us assume we rolled the dice for second time again we may get 1,2,3,4,5,6(any of these) the probability to get 3 is

Favourable chances=1

total chances=6

probability=\frac{1}{6}

the probability to get 3 in second roll irrespective of first one is \frac{1}{6}

the probability to get 4 in first time and then 3 is

The probability to occur both events at a time is multiplication of individual probabilities

So,

probablility to get 4 in first roll=\frac{1}{6}

probability to get 3 in second roll=\frac{1}{6}

probability to occur both at a same time is =\frac{1}{6} \times\frac{1}{6}=\frac{1}{36}

6 0
3 years ago
What percent represents a ratio of 8 to 50
EleoNora [17]
The percentage of that ratio is 16%
The simplest way to find any percentage is to divide the numerator by the denominator.
in this case that would be 8/15=0.16
16/100=16%
3 0
3 years ago
Read 2 more answers
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