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zmey [24]
3 years ago
11

If a student didn’t understand proportional relationships, how would you explain it to them?

Mathematics
2 answers:
kirill [66]3 years ago
7 0

Answer:

Proportional relationships are relationships between two variables where their ratios are equivalent.

Another way to think about them is that, in a proportional relationship, one variable is always a constant value times the other. That constant is know as the "constant of proportionality".

I really recommend watching Khan Academy's video over proportional relationships, the speaker explains it very well!!

goldfiish [28.3K]3 years ago
6 0

Answer:

watch

Don't Memorise

Step-by-step explanation:

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99%, because as the level of confidence​ increases, Zc increases.

Step-by-step explanation:

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3 years ago
Yvette uses 6 games of tea leaves to make 24
ruslelena [56]

Answer:

Therefore last week Yvette used 72 grams of tea leaves to make 288 ounces of tea.

Step-by-step explanation:

i) 6 grams of tea leaves are used to make 24 ounces of tea.

ii) 1 gram of tea leaves can be used to make  = \frac{24}{6} = 4\hspace{0.1cm}ounces\hspace{0.1cm}of\hspace{0.1cm}tea

iii)  number of grams of tea leaves to make 288 ounces of tea

  = \frac{288}{4} = 72\hspace{0.1cm}grams\hspace{0.1cm}of\hspace{0.1cm}tea\hspace{0.1cm}leaves

The answer is 72 grams of tea leaves are required to make 288 ounces of tea.

Therefore last week Yvette used 72 grams of tea leaves to make 288 ounces of tea.

8 0
3 years ago
Help please and thank you!!
Virty [35]

Answer:

30 and 17

Step-by-step explanation:

Using Pythagoras' theorem, that is

The square on the hypotenuse of a right triangle is equal to the sum of the squares on the other 2 sides, thus

(1)

c² = 18² + 24² = 324 + 576 = 900

Take the square root of both sides

c = \sqrt{900} = 30

(2)

c² = 8² + 15² = 64 + 225 = 289

Take the square root of both sides

c = \sqrt{289} = 17


5 0
3 years ago
Elimination: <br> 3x-4y=16<br> 5x+6y=14
Vlad [161]
\left \{ {{3x-4y=16\ \ | * (-5)} \atop {5x+6y=14 \ \ | *3}} \right. \\\\  \left \{ {{-15x+20y=-80} \atop {15x+18y=42}} \right. \\+-----\\add\ both \ equations\\\\&#10;38y=-38\ \ \ | divide\ by\ 38\\\\&#10;y=-1\\\\&#10;3x=16+4y\\\\&#10;x=\frac{16+4y}{3}=\frac{16+4*(-1)}{3}=\frac{12}{3}=4\\\\ \left \{ {{y=-1} \atop {x=4}} \right.
8 0
3 years ago
Read 2 more answers
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