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katen-ka-za [31]

3 years ago

13

A women who is 5 feet 5 inches tall is standing near the Space Needle in Seattle, Washington. She casts a 13-inch shadow at the

same time that the Space Needle casts a 121 foot shadow. How tall is the Space Needle

1 answer:

Varvara68 [4.7K]3 years ago

3 0

The space needle if 605 ft. high

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What is the difference between a postulate and a theorem

Novosadov [1.4K]

Theorem — a mathematical statement that is proved using rigorous mathematical reasoning. In a mathematical paper, the term theorem is often reserved for the most important results.

Postulate — a statement that is assumed to be true without proof. These are the basic building blocks from which all theorems are proved

6 0

4 years ago

What’s two plus three

Alex73 [517]

Answer:

Two plus three is five.

Hope this helps!

4 0

3 years ago

Read 2 more answers

OABC is a tetrahedron and OA=a, OB=b, and OC=c. The point P and Q are such that OA =AP and 2OB = BQ. The point M is a midpoint o

kondaur [170]

Given

.OABC is a tetrahedron

OA=a, OB=b, and OC=c.

point P and Q are such that OA =AP and 2OB = BQ

point M is a midpoint of PQ.

Find AB ,PQ, CQ ,QM ,MB ,OM in terms of a, b, and c.

To proof

we proof this by using the Triangle law of vector addition

when two vectors are represented by two sides of a triangle in magnitude and direction taken in same order then third side of the third side of that triangle represents in magnitude and direction the resultant of the vectors.

by using the diagram as shown below

$\vec{OA}=\vec{a}, \vec{OB}=\vec{b}\\\vec{OP}=2\vec{a},\vec{OQ}=3\vec{b}$

$\vec{OA}+\vec{AB}=\vec{OB}\\\vec{AB}=\vec{b}-\vec{a}$

$\vec{OP}+\vec{PQ}=\vec{OQ}\\\vec{PQ}=3\vec{b}-2\vec{a}$

$\vec{OC}+\vec{CQ}=\vec{OQ}\\\vec{CQ}=3\vec{b}-2\vec{c}\\\vec{QM}=-\frac{1}{2}\vec{PQ}\\$

$\vec{QM}=\vec{a}-\frac{3}{2}\vec{b}\\\vec{OM}=\vec{OQ}+\vec{QM}$

$\vec{OM}=\vec{a}+\frac{3}{2}\vec{b}\\\vec{MB}=-\vec{a}-\frac{1}{2}\vec{b}$

hence proved

6 0

3 years ago

Find the distance between points (0,-8) and (3,-2)

kompoz [17]

$\bf~~~~~~~~~~~~\textit{distance between 2 points} \\\\ (\stackrel{x_1}{0}~,~\stackrel{y_1}{-8})\qquad (\stackrel{x_2}{3}~,~\stackrel{y_2}{-2})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ d=\sqrt{[3-0]^2+[-2-(-8)]^2}\implies d=\sqrt{(3-0)^2+(-2+8)^2} \\\\\\ d=\sqrt{3^2+6^2}\implies d = \sqrt{9+36}\implies d=\sqrt{45}\implies d\approx 6.71$

7 0

3 years ago

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Solve to find the value of x. -5x=75<br><br> I need help

san4es73 [151]

Answer:

x= -15

Step-by-step explanation:

Divide to both sides by -5 to isolate the variable.

<u>-5x</u>=<u>75</u>

-5 -5

x= -15

This gives you the answer of x= -15.

3 0

3 years ago