Answer: 4.34
Step-by-step explanation:
Answer:
Hence after 3.98 sec i.e 4 sec Object will hit the ground .
Step-by-step explanation:
Given:
Height= 6 feet
Angle =28 degrees.
V=133 ft/sec
To Find:
Time in seconds after which it will hit the ground?
Solution:
<em>This problem is related to projectile motion for objec</em>t
First calculate the Range for object and it is given by ,
(2Ф)/
Here R= range g= acceleration due to gravity =9.8 m/sec^2
1m =3.2 feet
So 9.8 m, equals to 9.8 *3.2=31.36 ft
So g=31.36 ft/sec^2. and 2Ф=2(28)=56


fts
Now using Formula for time and range as

Vx is horizontal velocity
Ф
(28)
ft/sec
So above equation becomes as ,


T is approximately equals to 4 sec.
Hope you won't be turned off by a correction, but we really need to use the symbol " ^ " to denote exponentiation.
Thus, we have x^2 = 100
Taking the square root of both sides, we get x = plus or minus 10. Verify, please, that both x = -10 and x = +10 satisfy the given equation.
Answer:
1,712,304 ways
Step-by-step explanation:
This problem bothers on combination
Since we are to select 5 subjects from a pool of 48 subjects, the number of ways this can be done is expressed as;
48C5 = 48!/(48-5)!5!
48C5 = 48!/43!5!
48C5 = 48×47×46×45×44×43!/43!5!
48C5 = 48×47×46×45×44/5!
48C5 = 205,476,480/120
48C5 = 1,712,304
Hence this can be done in 1,712,304ways
The equation of the line is 
<u>Step-by-step explanation:</u>
- The line passes through the point (2,-4).
- The line has the slope of 3/5.
To find the equation of the line passing through a point and given its slope, the slope-intercept form is used to find its equation.
<u>The equation of the line when a point and slope is given :</u>
⇒ 
where,
- m is the slope of the line.
- (x1,y1) is the point (2.-4) in which the line passes through.
Therefore, the equation of the line can be framed by,
⇒ 
⇒ 
Take the denominator 5 to the left side of the equation.
⇒ 
Now, multiply the number outside the bracket to each term inside the bracket.
⇒ 
⇒ 
Divide by 5 on both sides of the equation,
⇒ 
Therefore, the equation of the line is 