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Nuetrik [128]
2 years ago
5

What is 7.69/43.685=? including long division I'll give brainliest.

Mathematics
2 answers:
Minchanka [31]2 years ago
8 0

Question

what is 7.69/43.685=?

Answer:

The Correct Answer is 5.6 :)

Step-by-step explanation:

Change the divisor 7.69 to a whole number by moving the decimal point 2 places to the right. Then move the decimal point in the dividend the same, 2 places to the right.

We then have the equations:

4368.5 ÷ 769 = 5.6

and therefore:

43.685 ÷ 7.69 = 5.6

Both calculated to 1 decimal places.

Rom4ik [11]2 years ago
7 0

Answer:

0.17603296326

Step-by-step explanation:

hope this helps

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Joey has a full 40 coins consisting of only quarters and nickels if the total value is $5.00 how many of each does joey have.
Archy [21]
Q + n = 40....q = 40 - n
0.25q + 0.05n = 5

0.25(40 - n) + 0.05n = 5
10 - 0.25n + 0.05n = 5
-0.25n + 0.05n = 5 - 10
 - 0.20n = -5
n = -5 / -0.20
n = 25 <=== 25 nickels

q + n = 40
q + 25 = 40
q = 40 - 25
q = 15 <== 15 quarters
7 0
3 years ago
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95 points <br><br> Simplify (4^9/4^3)^5 Show your work for full credit
dexar [7]

Answer:

  • 4^{30}

Step-by-step explanation:

  • (4^9/4^3)^5=
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  • (4^6)^5=
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3 0
2 years ago
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the starving actors guild holds its annual winter arts festival in hopes of raising $13,344 by selling 824 tickets. The guild ch
kap26 [50]
A + c = 824                             represents number of tickets to sell
20a + 12c = 13,344                represents cost of each type of ticket

multiply equation 1 by -12 to cancel the variable 'c' and solve for 'a'

-12(a + c = 824)

-12a - 12c = - 9888
 20a + 12c = 13,344         add equations together
-----------------------------
    8a          = 3456           divide both sides by 8
     a = 432

To find children's tickets substitute adult numbers back into equation 1.
a + c = 824
432 + c = 824
subtract 432 from both sides
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8 0
3 years ago
How many equivalence relations are there on the set 1, 2, 3]?
Alex787 [66]

Answer:

We need to find how many number of equivalence relations are on the set {1,2,3}

A relation is an equivalence relation if it is reflexive, transitive and symmetric.

equivalence relation R on {1,2,3}

1.For reflexive, it must contain (1,1),(2,2),(3,3)

2.For transitive, it must satisfy: if (x,y)∈R then (y,x)∈R

3. For symmetric, it must satisfy: if (x,y)∈R,(y,z)∈R then (x,z)∈R

Since (1,1),(2,2),(3,3) must be there is R, (1,2),(2,1),(2,3),(3,2),(1,3),(3,1). By symmetry,

we just need to count the number of ways in which we can use the pairs (1,2),(2,3),(1,3) to construct equivalence relations.

This is because if (1,2) is in the relation then (2,1) must be there in the relation.

the relation will be an equivalence relation if we use none of these pairs (1,2),(2,3),(1,3) . There is only one such relation: {(1,1),(2,2),(3,3)}

we can have three possible equivalence relations:

{(1,1),(2,2),(3,3),(1,2),(2,1)}

{(1,1),(2,2),(3,3),(1,3),(3,1)}

{(1,1),(2,2),(3,3),(2,3),(3,2)}

6 0
3 years ago
X^2-7x-6=0<br> Use the quadratic formula to complete the equation show step by step
asambeis [7]

Answer:

x  = 7  ± √73   / 2



3 0
3 years ago
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