Question

How many solutions do −2(3x−10)+8x=7x+20+7x have

Answer 1

Answer:

x=0

Step-by-step explanation:

Answer 2

2(3x-10)+8x=7x+20+7

We move all terms to the left:

-2(3x-10)+8x-(7x+20+7)=0

We add all the numbers together, and all the variables

-2(3x-10)+8x-(7x+27)=0

We add all the numbers together, and all the variables

8x-2(3x-10)-(7x+27)=0

We multiply parentheses

8x-6x-(7x+27)+20=0

We get rid of parentheses

8x-6x-7x-27+20=0

We add all the numbers together, and all the variables

-5x-7=0

We move all terms containing x to the left, all other terms to the right

-5x=7

x=7/-5

x=-1+2/5