Answer:
-1/6x + y = -5 or option D
Step-by-step explanation:
standard form is ax + by = c
Welp looks like I won't be seeing that cat, darn it
Answer:
x=−2
y=7
Step-by-step explanation:
5x+2y=4
x−3y=−23
In order to solve by elimination, coefficients of one of the variables must be the same in both equations so that the variable will cancel out when one equation is subtracted from the other.
5x+2y=4,x−3y=−23
To make 5x and x equal, multiply all terms on each side of the first equation by 1 and all terms on each side of the second by 5.
5x+2y=4,5x+5(−3)y=5(−23)
Simplify.
5x+2y=4,5x−15y=−115
Subtract 5x−15y=−115 from 5x+2y=4 by subtracting like terms on each side of the equal sign.
5x−5x+2y+15y=4+115
Add 5x to −5x. Terms 5x and −5x cancel out, leaving an equation with only one variable that can be solved.
2y+15y=4+115
Add 2y to 15y.
17y=4+115
Add 4 to 115.
17y=119
Divide both sides by 17.
y=7
Substitute 7 for y in x−3y=−23. Because the resulting equation contains only one variable, you can solve for x directly.
x−3×7=−23
Multiply −3 times 7.
x−21=−23
Add 21 to both sides of the equation.
x=−2
The system is now solved.
x=−2,y=7
Graph if needed:
<h3>
Answer: Choice A. x^2+9</h3>
This is a sum of squares, which cannot be factored over the real numbers. You'll need to involve complex numbers to be able to factor, though its likely your teacher hasn't covered that topic yet (though I could be mistaken and your teacher has mentioned it).
Choice B can be factored through the difference of squares rule. Therefore, choice B is not prime.
Choice C and D can be factored by pulling out the GCF and then use the difference of squares rule afterward. So we can rule out C and D as well.
Answer:
4/3 1.333 1 1/3
Step-by-step explanation: