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nordsb [41]
3 years ago
14

For the sequence an = 3n/(n + 1), what is the value of 210? Enter your answer as a fraction.

Mathematics
2 answers:
joja [24]3 years ago
5 0

Answer:

im just seeing what this app does

Svetradugi [14.3K]3 years ago
3 0

Answer:

the answer is 30/11 ...... I just did this

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HELP ME ASAP!!!
nadezda [96]

Answer:

1 \frac{7}{12}

3 \frac{19}{24}

8 \frac{3}{10}

5 \frac{1}{7}

5 \frac{5}{12}

3 \frac{11}{15}

Step-by-step explanation:

To add or subtract you need to make the denominator the same. To do this you need to find the least common multiple.

7 0
3 years ago
Read 2 more answers
WILL GIVE BRAINLIEST& 15 PTS.
kicyunya [14]

Answer:

The given fraction \frac{x^3-x^2}{x^3} reduces to  \frac{x-1}{x}

Step-by-step explanation:

Consider the given fraction \frac{x^3-x^2}{x^3}

We have to reduce the fraction to the lowest terms.

Consider numerator x^3-x^2

We can take x² common from both the term,

Thus, numerator can be written as x^2(x-1)

Given expression can be rewritten as ,

\frac{x^3-x^2}{x^3}=\frac{x^2(x-1)}{x^3}

We can now cancel x^2 from both numerator and denominator,

\Rightarrow \frac{x^2(x-1)}{x^3}=\frac{x^2(x-1)}{x^2 \cdot x}

\Rightarrow \frac{(x-1)}{x^2 \cdot x}=\frac{x-1}{x}

Thus, the given fraction \frac{x^3-x^2}{x^3} reduces to  \frac{x-1}{x}

6 0
3 years ago
Read 2 more answers
What is the end behavior for f(x)=4x^4+2x^3-13x^2-14x+24?
Tpy6a [65]

Answer:

This means that f(x)→∞ as x→−∞ and f(x)→∞ as x→∞.

Step-by-step explanation:

Since the leading term of the polynomial (the term in a polynomial which contains the highest power of the variable) is x4, then the degree is 4, i.e. even, and the leading coefficient is 1, i.e. positive.

This means that f(x)→∞ as x→−∞ and f(x)→∞ as x→∞.

8 0
3 years ago
14,000,000 in scentific notation
Anni [7]
           7
1.4x10^

Hope this helps!!!!!!!!!
7 0
4 years ago
Read 2 more answers
Please help I would really appreciate it :)
aleksley [76]

yo i dont know the answer but i hope you have a good day

6 0
3 years ago
Read 2 more answers
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