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bija089 [108]
3 years ago
10

From 2000 to 2003, the number of employees at a certain company increased by a factor of 1/4. From 2003 to 2006, the number of e

mployees at this company decreased by a factor of 1/3. If there were 100 employees at the company in 2006, how many employees were there at the company in 2000 ?
A. 200
B. 120
C. 100
D. 75
E. 60
Business
1 answer:
Rina8888 [55]3 years ago
6 0

Answer:

Let's assume that "X" be the number of employees in 2000.

∵ it's given :

From 2000 to 2003: the number of employees increased by a factor of 1/4

From 2003 to 2006: the number of employees decreased by a factor of 1/3

∴ We can equate the following details:

X×(increase in employee)×(decrease in employee) = 100

X×(1+\frac{1}{4})×(1-\frac{1}{3}) = 100  

X×(\frac{5}{4})×(\frac{2}{3}) = 100  

X×(\frac{10}{12}) = 100  

X = 100×(\frac{12}{10})  

<em>X = 120  </em>

<u><em>Therefore, the correct option is (b)</em></u>

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Consider the supply curve for basketballs. Other things held constant, if the price of basketballs goes up from $7. 99 to $14. 9
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There will be an increase in quantity supplied. (The Law of Supply)

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2 years ago
An investment project has annual cash inflows of $4,200, $5,100, $6,300, and $5,500, and a discount rate of 15 percent. a. What
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Answer:

It will take 1 year and 307 days to cover the initial investment.

Explanation:

Giving the following information:

Initial investment= $6,900

Cash flows:

Cf1= $4,200

Cf2= $5,100

Cf3= $6,300

Cf4= $5,500

Discount rate= 15%

<u>The payback period is the time required to cover the initial investment. We need to discount each cash flow.</u>

<u></u>

Year 1= 4,200/1.15 - 6,900= -3,247.83

Year 2= 5,100/1.15^2 - 3,247.83= 608.50

<u>To be more accurate:</u>

(3,247.83 / 3,856.33)*365= 307 days

It will take 1 year and 307 days to cover the initial investment.

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