The maximum weight that could be held would be 32 pounds. or six five pound weights taking up 18 inches of space, and weighing 30 Lbs, and two one pound weights adding another two inches. You could achieve a greater weight if you had a weight of one-half inch, in which case you could take six 5 lb weights and 1 two pound weight, then you could add a half inch weight bringing the weight to over 32 inches. Since we don't have a half inch weight we can't raise the weight above 32lbs.
Answer:
x = 55
Step-by-step explanation:
For PQ and RS to be parallel then
∠ACQ = ∠RDB ( Alternate exterior angles ), thus
3x - 65 = 2x - 10 ( subtract 2x from both sides )
x - 65 = - 10 ( add 65 to both sides )
x = 55
Answer:
-8 is the solution
Step-by-step explanation:


Answer:
18
Step-by-step explanation:
Since he does 90 cars-----5 days
x cars--------1 day
we multiply 90 by 1 then over 5
Answer: x= 6/35
Explanation