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Dima020 [189]
3 years ago
13

I need help with my recrystallization lab. I need help with answering the questions and for someone to check my work.

Chemistry
1 answer:
Igoryamba3 years ago
3 0
Answer:
What is the question
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A sample of oxygen gas was collected via water displacement. since the oxygen was collected via water displacement, the sample i
mylen [45]

The sample of oxygen gas was collected through water displacement. So, the gas collected will be a mixture of oxygen and water vapor.

Given that the total pressure of the mixture of gases containing oxygen and water vapor = 749 Torr

Vapor pressure of pure water at 26.4^{0}C=25.81mmHg

                               = 25.81 mmHg*\frac{1 Torr}{1 mmHg} =25.81 Torr

According to Dalton's law of partial pressures,

Total pressure = Partial pressure of Oxygen gas + Partial pressure of water

  749 Torr = Partial pressure of Oxygen gas + 25.81 Torr

Partial pressure of Oxygen gas = 749 Torr - 25.81 Torr =  723.19 Torr

Therefore the partial pressure of Oxygen gas in the mixture collected will be 723.19 Torr


6 0
4 years ago
Why is mining for coal a long-term concern?
Delvig [45]

Answer:

B

Explanation:

Coal is a non-renewable resource, so the supply can't produce faster than we can mine it.

8 0
3 years ago
Read 2 more answers
1. Most fruit juices are a solution of water, sugar, and fruit-specific chemicals. In this solution, identify the solvent and so
lianna [129]
In this case, we can say that water is the solvent. Solvent by definition are the part of the solution that is present in the largest amount. The fruit juice are all dilute by the water. Everything else in the fruit juice can be called the solute, they are what is "dissolved" in the solvent (sugar, fruit juice, etc.).   

Hoped I helped!
5 0
4 years ago
Use the standard half-cell potentials listed below to calculate the standard cell potential for the following reaction occurring
iren2701 [21]

Answer:

1.20 V

Explanation:

The standard cell potential is calculated from the expression

ε⁰ cell = ε⁰ oxidation + ε⁰  reduction

The species that will be reduced is the one with the higher standard reduction potential and the species that will be oxidized will be the one with the more negative reduction potential.

Thus for our question we will have

oxidation:

Pb(s)  →   Pb2+(aq) + 2 e-       ε⁰ oxidation       =  -   ε⁰  reduction

                                                                          =   - ( - 0.13 V ) = + 0.13 V

reduction    

Br2(l) + 2 e- → 2 Br-(aq)           ε⁰  reduction     = +1.07 V

ε⁰ cell = ε⁰ oxidation + ε⁰  reduction = + 0.13 V + 1.07 V  = 1.20 V

4 0
3 years ago
Deposition of sediment will most likely form a
Ierofanga [76]
I would say delta reason: Sediments are deposited throughout the length of the stream as bars or floodplain deposits. At the mouth of the stream, the sediments are usually deposited in alluvial fans or deltas, which represent a lower‐energy, more “permanent” depositional environment that is less susceptible to changes in the stream
5 0
3 years ago
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