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creativ13 [48]
3 years ago
6

How many grams of Cl2 will be produced along with 250.0 kJ of heat in the following reaction? PCl5(g) + 87.9 kJ PCl3(g) + Cl2(g)

Chemistry
2 answers:
Serjik [45]3 years ago
5 0

As per the given chemical equation, 1 mole of Cl₂ is formed when 87.9 kJ of heat is absorbed.

Therefore, 250.0 kJ of heat will yield

\frac{1 mol Cl2}{87.9 kJ } \\  x 250.0 kJ = 2.84 mol Cl₂

Molar mass of mol Cl₂ = 71 g /mol

Mass of Cl₂ =2.84 mol Cl₂ x 71 g /mol = 201.64 g

201.64 g of Cl₂ will be produced along with 250.0 kJ of heat in the given reaction.

AfilCa [17]3 years ago
3 0
250 kJ/87.9 KJ per mole Cl2 * 71g/mole= 202 g It is D for plato users
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4HCl(g)+O2(g)⟶2Cl2(g)+2H2O(g) Calculate the number of grams of Cl2 formed when 0.385 mol HCl reacts with an excess of O2. mass:
FromTheMoon [43]

The number of grams of Cl2 formed when 0.385 mol HCl reacts with an excess of O2 is 13.6675 g.

<h3>What are moles?</h3>

A mole is defined as 6.02214076 × 10^{23} of some chemical unit, be it atoms, molecules, ions, or others. The mole is a convenient unit to use because of the great number of atoms, molecules, or others in any substance.

Given data:

Moles of hydrochloric acid = 0.385 mol

Mass of chlorine gas =?

Chemical equation:

4HCl +  O₂ → 2Cl₂  + 2H₂O

Now we will compare the moles of Cl₂ with HCl.

                 HCl           :               Cl₂

                   4             :               2

                0.385       :              2÷4× 0.385 = 0.1925 mol

Oxygen is present in excess that's why the mass of chlorine produced depends upon the available amount of HCl.

Mass of Cl₂ :

Mass of Cl₂ = moles × molar mass

Mass of Cl₂ =0.1925 mol × 71 g/mol

Mass of Cl₂ =  13.6675 g

Hence, the number of grams of Cl2 formed when 0.385 mol HCl reacts with an excess of O2 is 13.6675 g.

Learn more about moles here:

brainly.com/question/8455949

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