1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
creativ13 [48]
3 years ago
6

How many grams of Cl2 will be produced along with 250.0 kJ of heat in the following reaction? PCl5(g) + 87.9 kJ PCl3(g) + Cl2(g)

Chemistry
2 answers:
Serjik [45]3 years ago
5 0

As per the given chemical equation, 1 mole of Cl₂ is formed when 87.9 kJ of heat is absorbed.

Therefore, 250.0 kJ of heat will yield

\frac{1 mol Cl2}{87.9 kJ } \\  x 250.0 kJ = 2.84 mol Cl₂

Molar mass of mol Cl₂ = 71 g /mol

Mass of Cl₂ =2.84 mol Cl₂ x 71 g /mol = 201.64 g

201.64 g of Cl₂ will be produced along with 250.0 kJ of heat in the given reaction.

AfilCa [17]3 years ago
3 0
250 kJ/87.9 KJ per mole Cl2 * 71g/mole= 202 g It is D for plato users
You might be interested in
What is the composition of 'Clean dry air'<br><br> - Idk what subject its just science
Luba_88 [7]
Dry air is a mixture of nitrogen, oxygen, carbon dioxide etc.
air is a mixture of gases 78% nitrogen an 21% oxygen and other components.
7 0
3 years ago
What are some factors that affect weather?
Zarrin [17]
B is the right answer
6 0
3 years ago
HELP PLEASE WILL GIVE BRAINLIEST
Crank

Answer:

Option D. Al is above H on the activity series.

Explanation:

The equation for the reaction is given below:

2Al + 6HBr —> 2AlBr₃ + 3H₂

The activity series gives us a background understanding of the reactivity of elements i.e how elements displace other elements when present in solution.

From the activity series of metals, we understood that metal higher in the series will displace those lower in the series.

Considering the equation given above, Al is higher than H in the activity series. Thus, the reaction will proceed as illustrated by the equation.

Therefore, we can conclude that the reaction will only occur if Al is higher than H in the activity series.

4 0
3 years ago
___ Au₂S₃ + ___ H₂ → ___ Au + ___ H₂S
Natalija [7]

Answer:

2Au₂S₃ +  6H₂ → 4Au + 6H₂S

Explanation:

Balancing:

2Au₂S₃ +  6H₂ → 4Au + 6H₂S

6 0
3 years ago
Consider 100.0 g samples of two different compounds consisting only of carbon and oxygen. One compound contains 27.2 g of carbon
Pani-rosa [81]

<u>Answer:</u> The ratio of carbon in both the compounds is 1 : 2

<u>Explanation:</u>

Law of multiple proportions states that when two elements combine to form two or more compounds in more than one proportion. The mass of one element that combine with a given mass of the other element are present in the ratios of small whole number. For Example: Cu_2O\text{ and }CuO

  • <u>For Sample 1:</u>

Total mass of sample = 100 g

Mass of carbon = 27.2 g

Mass of oxygen = (100 - 27.7) = 72.8 g

To formulate the formula of the compound, we need to follow some steps:

  • <u>Step 1:</u> Converting the given masses into moles.

Moles of Carbon =\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{27.2g}{12g/mole}=2.26moles

Moles of Oxygen = \frac{\text{Given mass of oxygen}}{\text{Molar mass of oxygen}}=\frac{72.8g}{16g/mole}=4.55moles

  • <u>Step 2:</u> Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 2.26 moles.

For Carbon = \frac{2.26}{2.26}=1

For Oxygen  = \frac{4.55}{2.26}=2.01\approx 2

  • <u>Step 3:</u> Taking the mole ratio as their subscripts.

The ratio of C : O = 1 : 2

Hence, the formula for sample 1 is CO_2

  • <u>For Sample 2:</u>

Total mass of sample = 100 g

Mass of carbon = 42.9 g

Mass of oxygen = (100 - 42.9) = 57.1 g

To formulate the formula of the compound, we need to follow some steps:

  • <u>Step 1:</u> Converting the given masses into moles.

Moles of Carbon =\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{42.9g}{12g/mole}=3.57moles

Moles of Oxygen = \frac{\text{Given mass of oxygen}}{\text{Molar mass of oxygen}}=\frac{57.1g}{16g/mole}=3.57moles

  • <u>Step 2:</u> Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 3.57 moles.

For Carbon = \frac{3.57}{3.57}=1

For Oxygen  = \frac{3.57}{3.57}=1

<u>Step 3:</u> Taking the mole ratio as their subscripts.

The ratio of C : O = 1 : 1

Hence, the formula for sample 1 is CO

In the given samples, we need to fix the ratio of oxygen atoms.

So, in sample one, the atom ratio of oxygen and carbon is 2 : 1.

Thus, for 1 atom of oxygen, the atoms of carbon required will be = \frac{1}{2}\times 1=\frac{1}{2}

Now, taking the ratio of carbon atoms in both the samples, we get:

C_1:C_2=\frac{1}{2}:1=1:2

Hence, the ratio of carbon in both the compounds is 1 : 2

8 0
3 years ago
Other questions:
  • A client at 39 weeks gestation with preeclampsia has a blood pressure of 170/100 mm Hg, 2+ proteinuria, and moderate peripheral
    6·1 answer
  • What the approximate mass of 24cm of silver, if the density is 10.5 g/cm
    13·1 answer
  • 73 m is equal to ____ dm. (Only input whole number answer.)
    5·2 answers
  • Consider this reaction:2HI(g) ------&gt; H2(g) + I2(g)At a certain temperature it obeys this rate law.rate = (8.74 x 10^-4s^-1)
    15·1 answer
  • Which one is an example of a chemical change please help
    11·1 answer
  • 0.50 g of hydrogen chloride (HCl) is dissolved in water to make 4.0 L of solution. What is the pH of the resulting hydrochloric
    7·1 answer
  • What is the balanced net ionic reaction for the following -<br>CaCl2 + Na2S --&gt; NaCl + CaS?​
    11·1 answer
  • Nal+ pb(SO4) 2 Pbl4 + Na2SO4 explain how to balance the chemical equation and classify its reaction type
    8·1 answer
  • How many atoms are present in 2g of hydrogen gas​
    7·1 answer
  • if a gas has an initial pressure of 24,650 pa and an initial volume of 376 ml, what is the final volume if the pressure of the g
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!