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krok68 [10]
3 years ago
11

What is the density of an object that has a mass of 21 g and a volume of 9 ml?

Chemistry
1 answer:
mylen [45]3 years ago
5 0

The formula is density = mass / Volume

density = ?

mass = 21 g

Volume = 9 mL

d = m / V

d = 21 g / 9 mL

d = 2.3 g/mL

Hope this help!


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Is exploding dynamite a chemical or physical property?
ankoles [38]
<span>the answer would be chemical</span>
5 0
3 years ago
Guess how many water molecules self-ionize in one liter of water! a) 7 moles b) 1 mole c) 10,000,000 moles d) 0.0000001 moles​
Rudiy27

Answer:

D)

Explanation:

This seems like a weird question

Water is held together by covalent bonds. The amount of energy required to break these bonds so that water would split into it's respective ions is pretty high. The chances that any one of the molecules floating in 1L of water get enough energy to spontaneously burst into it's ions is slim to none.

So, D) seems like the most likely answer

6 0
2 years ago
At 400 K oxalic acid decomposes according to the reaction:H2C2O4(g)→CO2(g)+HCOOH(g)In three separate experiments, the intial pre
padilas [110]

Answer:

v = 2,66x10⁻⁵ P[H₂C₂O₄]

Explanation:

For the reaction:

H₂C₂O₄(g) → CO₂(g) + HCOOH(g)

At t = 0, the initial pressure is just of H₂C₂O₄(g). At t= 20000 s, pressures will be:

H₂C₂O₄(g) = P₀ - x

CO₂(g) = x

HCOOH(g) = x

P at t=20000 is:

P₀ - x + x + x = P₀+x. That means P at t=20000s - P₀ = x

For 1st point:

x = 92,8-65,8 = 27

Pressure of H₂C₂O₄(g) at t=20000s: 65,8-27 = 38,8

2nd point:

x = 130-92,1 = 37,9

H₂C₂O₄(g): 92,1 - 37,9 = 54,2

3rd point:

x = 157-111 = 46

H₂C₂O₄(g): 111-46 = 65

Now, as the rate law is :

v = k P[H₂C₂O₄]

Based on integrated rate law, k is:

(- ln P[H₂C₂O₄] + ln P[H₂C₂O₄]₀) / t = k

1st point:

k = 2,64x10⁻⁵

2nd point:

k = 2,65x10⁻⁵

3rd point:

k = 2,68x10⁻⁵

The averrage of this values is:

k = 2,66x10⁻⁵

That means law is:

v = 2,66x10⁻⁵ P[H₂C₂O₄]

I hope it helps!

4 0
3 years ago
The nucleus is like the____of the cell
Tpy6a [65]

Answer:

Brain

Explanation:

It tells the other organelles how to do things

5 0
3 years ago
Read 2 more answers
Calculate the concentration of formate in a 100mm solution of formic acid at ph 4.15. The pka for formic acid is 3.75
MissTica

The molarity of formic acid is 100 mM or 100\times 10^{-3}M. The dissociation reaction of formic acid is as follows:

HCOOH\leftrightharpoons HCOO^{-}+H^{+}

The expression for dissociation constant of the reaction will be:

K_{a}=\frac{[HCOO^{-}][H^{+}]}{[HCOOH]}

Rearranging,

[HCOO^{-}]=\frac{K_{a}[HCOOH]}{[H^{+}]}

Here, pH of solution is 4.15 thus, concentration of hydrogen ion will be:

[H^{+}]=10^{-pH}=10^{-4.15}=7.08\times 10^{-5}M

Similarly, pK_{a}=3.75 thus,

[K_{a}=10^{-pK_{a}}=10^{-3.75}=1.78\times 10^{-4}M

Putting the values,

[HCOO^{-}]=\frac{(1.78\times 10^{-4}M)(100\times 10^{-3}M)}{(7.08\times 10^{-5}M}=0.2511 M

Therefore, the concentration of formate will be 0.2511 M.

4 0
3 years ago
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