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3 years ago

5

A table is 2 feet 6 inches long.There are 2.54 centimeters in one inch.What is the length of the table in centimeters? (7.4E,7.1

A,7.4E

1 answer:

Nesterboy [21]3 years ago

5 0

Answer:

79.248

Step-by-step explanation:

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Determine the quotient of 1 and 3 over 4 divided by 2 over 5 . (2 points)

Georgia [21]

Answer:

2/3 divided by 4/5

First we convert the denominators to a likewise number.

3 and 5 both share 15.

2 x 5 = 10

10/15

4 x 3 = 12

12/15

10/15 divided by 12/15

Correct answer should be 10 over 12.

Step-by-step explanation:

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Kazeer [188]

Answer:

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Step-by-step explanation:

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Find the integration of (1-cos2x)/(1+cos2x)

slega [8]

Given:

The expression is:

$\dfrac{1-\cos 2x}{1+\cos 2x}$

To find:

The integration of the given expression.

Solution:

We need to find the integration of $\dfrac{1-\cos 2x}{1+\cos 2x}$ .

Let us consider,

$I=\int \dfrac{1-\cos 2x}{1+\cos 2x}dx$

$I=\int \dfrac{2\sin^2x}{2\cos^2x}dx$ $[\because 1+\cos 2x=2\cos^2x,1-\cos 2x=2\sin^2x]$

$I=\int \dfrac{\sin^2x}{\cos^2x}dx$

$I=\int \tan^2xdx$ $\left[\because \tan \theta =\dfrac{\sin \theta}{\cos \theta}\right]$

It can be written as:

$I=\int (\sec^2x-1)dx$ $[\because 1+\tan^2 \theta =\sec^2 \theta]$

$I=\int \sec^2xdx-\int 1dx$

$I=\tan x-x+C$

Therefore, the integration of $\dfrac{1-\cos 2x}{1+\cos 2x}$ is $I=\tan x-x+C$ .

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3 years ago

Stanley is reading a 224-page book. There are illustrations on 14 pages. If Stanley opens the book at random, what is the probab

likoan [24]

It will be 0.0625 because you can use a calculator and do 14/224

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