Hello!
The graph, (2/5)^x is an exponential function.
Since there is not a negative symbol in the front of the function, options A and B are incorrect.
For option 3 to be correct, there would need to be a negative symbol in front of the exponent, x.
So therefore, the answer option 4. (Also, I'll post a graph. :))
Answer:
The equations that represent the reflected function are


Step-by-step explanation:
The correct question in the attached figure
we have the function

we know that
A reflection across the y-axis interchanges positive x-values with negative x-values, swapping x and −x.
therefore

The reflection of the given function across the y-axis will be equal to
(Remember interchanges positive x-values with negative x-values)

An equivalent form will be
![f(x)=5(\frac{1}{5})^{(-1)(x)}=5[(\frac{1}{5})^{-1})]^{x}=5(5)^{x}](https://tex.z-dn.net/?f=f%28x%29%3D5%28%5Cfrac%7B1%7D%7B5%7D%29%5E%7B%28-1%29%28x%29%7D%3D5%5B%28%5Cfrac%7B1%7D%7B5%7D%29%5E%7B-1%7D%29%5D%5E%7Bx%7D%3D5%285%29%5E%7Bx%7D)
therefore
The equations that represent the reflected function are


Answer:
MATH PROBLEM
Step-by-step explanation:
Answer:
Step-by-step explanation:
From the table attached,
x-intercept of the linear function is, the value of 'x' when f(x) = 0
x = 3 [x-intercept]
Function 'g' is the sum of 2 and the cube root of the sum of three time x and 1.
g(x) = ![2+\sqrt[3]{3x+1}](https://tex.z-dn.net/?f=2%2B%5Csqrt%5B3%5D%7B3x%2B1%7D)
For x-intercept,
g(x) = 0
![2+\sqrt[3]{3x+1}=0](https://tex.z-dn.net/?f=2%2B%5Csqrt%5B3%5D%7B3x%2B1%7D%3D0)
3x + 1 = (-2)³
3x + 1 = -8
3x = -8 - 1
3x = -9
x = -3
Therefore, the x-intercept of function 'f' is different or greater than the x-intercept of function g.