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AlexFokin [52]
3 years ago
15

I need help with this question giving brainliest

Mathematics
1 answer:
Bezzdna [24]3 years ago
5 0

Answer:

I hope it helps but all I can do in my head is x=3

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Which of the following is a defined term?<br> Angle<br> Line <br> Point<br> Plane
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Point is the defined term
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3 years ago
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(2pm^-1q^0)^-4 • 2m ^-1 p^3 / 2pq^2
Montano1993 [528]

Answer:

\dfrac{m^3}{16p^2q^2}

Step-by-step explanation:

Given:

(2pm^{-1}q^0)^{-4}\cdot \dfrac{ 2m^{-1} p^3}{2pq^2}

1.

m^{-1}=\dfrac{1}{m}

2.

q^0=1

3.

2pm^{-1}q^0=2p\cdot \dfrac{1}{m}\cdot 1=\dfrac{2p}{m}

4.

(2pm^{-1}q^0)^{-4}=\left(\dfrac{2p}{m}\right)^{-4}=\left(\dfrac{m}{2p}\right)^4=\dfrac{m^4}{(2p)^4}=\dfrac{m^4}{16p^4}

5.

m^{-1}=\dfrac{1}{m}

6.

2m^{-1} p^3=2\cdot \dfrac{1}{m}\cdot p^3=\dfrac{2p^3}{m}

7.

\dfrac{ 2m^{-1} p^3}{2pq^2}=\dfrac{\frac{2p^3}{m}}{2pq^2}=\dfrac{2p^3}{m}\cdot \dfrac{1}{2pq^2}=\dfrac{p^2}{mq^2}

8.

(2pm^{-1}q^0)^{-4}\cdot \dfrac{ 2m^{-1} p^3}{2pq^2}=\dfrac{m^4}{16p^4}\cdot \dfrac{p^2}{mq^2}=\dfrac{m^3}{16p^2q^2}

8 0
3 years ago
Lisa has to cut her grandma's grass this weekend and wants to know exactly how much area she will be cutting. Calculate the area
Amiraneli [1.4K]
I would use the formula, area = length x width
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The formula f= 1.8 + 32 is used to convert temputure from degrees celsius ºC to degrees
Svetach [21]

Answer:

The Formula F=1.8C+32 gives the temperature in degrees Celsius (C). There is one temperature for which a number of degrees Fahrenheit is equal to the number of degrees Celsius.

Step-by-step explanation:

20ºC = 68ºF i think this is equation.;-;

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the first ferris wheel was built in 1893 in chicago. It’s diameter was 250 feet. How many feet did the ferris wheel rotate with
Mice21 [21]

Answer:

about 785.4

Step-by-step explanation:

The circumference of a circle is pi times the diameter:

C = πd

C = π·(250 ft) ≈ 785.4 ft

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Most scientific or graphing calculators have the value of π built in. If yours doesn't, a value good for at least 6 significant figures is the ratio 355/113.

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