Ab^x
a: initial value
b: value remaining after depreciation per year (in percentage)
x: number of years that have passed
35000(0.95)^8= 23219.7151
Round to the nearest hundredth value:
About $23219.72
Let me know if you have any questions :)
Answer:
t = 7 + 3i
Step-by-step explanation:
(t-7)^2 + 18 = 9
(t-7)^2 = 9 - 18
(t-7)^2 = -9
(t-7) = sqrt(-9) = |3| sqrt(-1)
t = 7 + 3i
Answer:
15,000
Step-by-step explanation:
20% of 15,000 is 3,000. 15,000-3,000=12,000
Given:

To find:
The values of f(2) and f(5).
Solution:
If an ordered pair
is in the function
, then
.
In the given set of ordered pairs one ordered pair is (2,3). So, by using the above definition, we get

In the given set of ordered pairs one ordered pair is (5,6). So, by using the above definition, we get

Therefore, the value of f(2) is 3 and the value of f(5) is 6.