Question

The bottom of a box has a surface area of 31.4 cm2. The mass of the box is 47.1 kilograms. Acceleration due to gravity at sea level is 9.80 m/s2. What pressure is exerted by the box where it rests?
14.7 N
1.5 N
0.153 N
6.53 N

Answer 1

The correct answer to the physics problem in pressure given above would be 1.5 N.
 
First, I converted the cm^2 to m^ 2 (31.4 cm^2 = .00314 m^2).

Then I computed for the force (F= mg = (47.1kg)(9.8m/s^2) = 461.58 N) 

Consequently, I used the equation of pressure (P = Force/Area).
P = 461.58 N / .00314 m^2
P = 1.47 or 1.5 N

Answer 2

Answer:

Pressure = 147,000 N.

Step-by-step explanation:

Given : The bottom of a box has a surface area of 31.4 cm². The mass of the box is 47.1 kilograms. Acceleration due to gravity at sea level is 9.80 m/s².

To find :  What pressure is exerted by the box where it rests.

Solution : We have given that area of box = 31.4 cm²

First we convert it in meter².

1 meter = 100 cm

31.4 cm² = 0.00314 meter².

Mass of box = 47.1 kg

Acceleration due to gravity = 9.80 m/s².

According to Newton second law of motion , F = mass * Acceleration due to gravity.

F = 47.1 * 9.8

F = 461.58 Newton.

Pressure = $\frac{Force}{Area}$.

Plugging the values of force and area.

Pressure =  $\frac{ 461.58}{0.00314}$.Pressure

Pressure = 147,000 N.

Therefore, Pressure = 147,000 N.