A food truck operator is parked in a lot at the corner of two streets. She wants to be equidistant from both streets. Should she
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Check the picture below.
so the chord is the one in red there, making the segment, in green there, with a central angle of 45°, and the minor segment will be that green one.
![\bf \textit{area of a segment of a circle}\\\\ A=\cfrac{r^2}{2}\left[ \cfrac{\pi \theta }{180} - sin(\theta) \right]~~ \begin{cases} r=radius\\ \theta =angle~in\\ \qquad degrees\\ ------\\ r=3\\ \theta =45 \end{cases} \\\\\\ A=\cfrac{3^2}{2}\left[ \cfrac{\pi(45) }{180} - sin(45^o) \right]\implies A=\cfrac{9}{2}\left[ \cfrac{\pi }{4}-\cfrac{\sqrt{2}}{2} \right] \\\\\\ A=\cfrac{9}{2}\left( \cfrac{\pi -2\sqrt{2}}{4} \right)\implies A\approx 0.3523112199491](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Barea%20of%20a%20segment%20of%20a%20circle%7D%5C%5C%5C%5C%0AA%3D%5Ccfrac%7Br%5E2%7D%7B2%7D%5Cleft%5B%20%5Ccfrac%7B%5Cpi%20%5Ctheta%20%7D%7B180%7D%20-%20sin%28%5Ctheta%29%20%5Cright%5D~~%0A%5Cbegin%7Bcases%7D%0Ar%3Dradius%5C%5C%0A%5Ctheta%20%3Dangle~in%5C%5C%0A%5Cqquad%20degrees%5C%5C%0A------%5C%5C%0Ar%3D3%5C%5C%0A%5Ctheta%20%3D45%0A%5Cend%7Bcases%7D%0A%5C%5C%5C%5C%5C%5C%0AA%3D%5Ccfrac%7B3%5E2%7D%7B2%7D%5Cleft%5B%20%5Ccfrac%7B%5Cpi%2845%29%20%7D%7B180%7D%20-%20sin%2845%5Eo%29%20%5Cright%5D%5Cimplies%20A%3D%5Ccfrac%7B9%7D%7B2%7D%5Cleft%5B%20%5Ccfrac%7B%5Cpi%20%7D%7B4%7D-%5Ccfrac%7B%5Csqrt%7B2%7D%7D%7B2%7D%20%5Cright%5D%0A%5C%5C%5C%5C%5C%5C%0AA%3D%5Ccfrac%7B9%7D%7B2%7D%5Cleft%28%20%5Ccfrac%7B%5Cpi%20-2%5Csqrt%7B2%7D%7D%7B4%7D%20%5Cright%29%5Cimplies%20A%5Capprox%200.3523112199491)
so the chord is the one in red there, making the segment, in green there, with a central angle of 45°, and the minor segment will be that green one.
Formula for the surface area of a hexagonal prism: A = 6 * a * h + 3 
* a^2