Question

Abe is going to plant 54 oak trees and 27 pine trees. Abe would like to plant the trees in rows that all have the same number of trees and are made up of only one type of tree. What is the greatest number of trees Abe can have in each row?

Answer 1

Answer with explanation:

Number of oak trees =54

Number of pine trees =27

→Abe would like to plant the trees in rows that all have the same number of trees and are made up of only one type of tree.

We, will take H CF that is highest common factor of 54 and 27.

54 = 2×3×3×3

27=3×3×3

→H CF(54,27)=3 × 3×3=27

So, greatest number of trees Abe can have in each row =27,and there will be maximum of 3 rows, 2 containing oak tree because $\frac{54}{27}=2$, and one containing pine tree because$\frac{27}{27}=1$.

Answer 2

Answer: There are 27 trees that Abe can plant in each row. And there are 1 pine tree and 2 oak tree in each row.

Explanation:

Since we have given that

Number of oak trees = 54

Number of pine trees = 27

According to question, we have given that Abe wants to plant the trees in rows that all have the same number of trees and are made up of only one type of tree.

So, the greatest number of trees is given by

$H.C.F\ of\ 27\ and\ 54=27$

Hence, there are 27 trees that Abe can plant in each row.

Therefore, there are $\frac{27}{27}=1\text{ pine tree and }\frac{54}{27}=2\text{ oak trees.}$

Answer 3

27 trees 27/27