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Stels [109]
3 years ago
7

Only part B and C . please help.​

Mathematics
1 answer:
Stels [109]3 years ago
3 0

Answer:

Step-by-step explanation:

To determine if the given values are part of a right-angled triangle, we need to use the Pythagorean theorem, removing one of the variables, and if it results in the neglected value, it is a right-angled triangle.

a^2+b^2=c^2\\

b.

21^2+24^2=c^2\\c=31.9

DEF is not a right triangle.

c.

7.1^2+2.4^2=c^2\\c=7.5

GHI is a right triangle.

<em>Hope this helped! If you need more help with the practice, please comment below. Have a good day!</em>

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Prove that if a and b are positive integers whose sum is a prime p, their greatest common divisor is 1.
Tasya [4]

Proof by contadiction.

Let assume there exist such positive integers a and b whose sum is a prime number p, that their greatest common divisor is greater than 1.

a,b\in\mathbb{Z^+}\\d=\text{gcd}(a,b)>1\\\\a=de\\b=df\\e,f\in\mathbb{Z^+}\\\\a+b=p\\de+df=p\\d(e+f)=p\\

Since p is a prime number and d>1, then d=p \wedge e+f=1, but we assumed earlier that e,f\in\mathbb{Z^+}, and there are no two positive integers that sum up to 1.

q.e.d.

7 0
3 years ago
Identify whether the equation represents an exponential growth or exponential decay function.1. y = 1/4 (1/e)^-2x2. y = (1/e)^4x
zvonat [6]

The general formula for exponential growth and decays is:

y=y_0e^{kx}

if k>0 then then it is an exponential growth function. If k<0 then the function represents an exponential decay.

Now we need to classify each of the functions:

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The function

y=\frac{1}{4}(\frac{1}{e})^{-2x}

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\begin{gathered} y=\frac{1}{4}(e^{-1})^{-2x}^{} \\ =\frac{1}{4}e^{2x} \end{gathered}

comparing with the general formula we notice that k=2, therefore this is an exponential growth.

2.

The function

y=(\frac{1}{e})^{4x}

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\begin{gathered} y=(\frac{1}{e})^{4x} \\ y=(e^{-1})^{4x} \\ y=e^{-4x} \end{gathered}

comparing with the general formula we notice that k=-4, therefore this is an exponential decay.

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The function

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1 year ago
Why are there so many moose attacks
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Answer:

Moose attacks spike in September and October which is mating season, and early Spring also due to young calves being raised. Many moose attacks on humans are actually provoked from dogs. Moose hate dogs and wolves, and become extremely aggressive by their presence, especially at a dog that barks.

7 0
2 years ago
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Please help asap! Will give brainliest! Please read the question then answer correctly! No guessing.
frutty [35]

Answer:

(x - 5) (x - 7)

Step-by-step explanation:

<em><u>To factor this trinomial, you must split the middle term (-12x) into two terms that can be added to get -12x, and multiplied to get 35:</u></em>

<em><u /></em>x^2 - 12x + 35

x^2 -7x - 5x + 35

<em><u>Group:</u></em>

(x^2 -7x) (-5x + 35)

<em><u>Take out the GCF (Greatest Common Factor):</u></em>

x(x - 7)  -5(x - 7)

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What is the value of y in the figure below? (Picture provided)
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