Can someone help me with this? ^_^<br> 4(-3f-4)-9f4(−3f−4)−9f

Find the values of x and y.

olchik [2.2K]

Answer:

value of x = 26

value of y = 26 \|2

( 26 root 2 )

Step-by-step explanation:

here's the solution : -

=》

$\sin(45) = \frac{perpendicular}{hypotenuse}$

=》

$\frac{1}{ \sqrt{2} } = \frac{26}{y}$

=》

$y = 26 \sqrt{2}$

and

$\tan(45) = \frac{perpendicular}{base}$

=》

$1 = \frac{26}{x}$

=》

$x = 26$

8 0

3 years ago

How to solve this kind of question?

S_A_V [24]

<span>96 degrees Looking at the diagram, you have a regular pentagon on top and a regular hexagon on the bottom. Towards the right of those figures, a side is extended to create an irregularly shaped quadrilateral. And you want to fine the value of the congruent angle to the furthermost interior angle. So let's start. Each interior angle of the pentagon has a value of 108. The supplementary angle will be 180 - 108 = 72. So one of the interior angles of the quadrilateral will be 72. From the hexagon, each interior angle is 120 degrees. So the supplementary angle will be 180-120 = 60 degrees. That's another interior angle of the quadrilateral. The 3rd interior angle of the quadrilateral will be 360-108-120 = 132 degrees. So we now have 3 of the interior angles which are 72, 60, and 132. Since all the interior angles will add up to 360, the 4th angle will be 360 - 72 - 60 - 132 = 96 degrees. And since x is the opposite (or congruent) angle to this 4th interior angle, it too has the value of 96 degrees.</span>

5 0

3 years ago

Read 2 more answers

In f(x) = 2x2 − 8x − 10, the y-intercept is ? at ? and the x-intercepts are (-1, 0) and ? .

IgorLugansk [536]

<h2>1. y-intercept</h2>

$\boxed{(0,-10)}$

The quadratic function $f(x)=2x^22-8x-10$ represents a parabola. In fact, the graph of a quadratic function is a special type of U-shaped curve called a parabola. To find the y intercept, we set $x=0$ as follows:

$f(x)=2x^2-8x-10 \\ \\ If \ x=0 \rightarrow f(0)=-10 \\ \\ Then \ y-intercept: \\ \\ (0,-10)$

<h2>2. x-intercepts</h2>

$\boxed{(-1,0) \ and \ (5,0)}$

To find the other x-intercept, we must set $y=0$ as follows:

$f(x)=2x^2-8x-10 \\ \\ If \ y=0 \rightarrow 2x^2-8x-10=0 \\ \\ Using \ the \ quadratic \ formula: \\ \\ x=\frac{-b \pm \sqrt{b^2-4ac}}{2a} \\ \\ \therefore x=\frac{-(-8) \pm \sqrt{(-b)^2-4(2)(-10)}}{2(2)} \\ \\ \therefore x_{1}=-1 \ and \ x_{2}=5$