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2 years ago

The volume of a cube is 27 cm^3 . Find the length of the side. Help please

Mathematics

1 answer:

a_sh-v [17]2 years ago

5 0

Answer:a=3cm

Step-by-step explanation:

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4) A garden is in the shape of a square with a perimeter of

Leni [432]

Answer:

It costs $154.88 to build the fences.

Step-by-step explanation:

Perimeter of square = $4 \times Side$

We are given that A garden is in the shape of a square with a perimeter of 56 feet.

So, $4 \times side = 56$

Side = $\frac{56}{4}=14 feet$

So, Side of square park = 14 feet

One fence is around the perimeter of the garden, whereas the second fence is 2 feet from the first fence on the outside.

Outer length = 14+2+2=18 feet

So, Perimeter of outer fence = $4 \times side = 4 \times 18 = 72 feet$

Cost of fencing 1 foot = $1.21

Cost of fencing 56 feet = $56 \times 1.21=67.76$

Cost of fencing 72 feet = $72 \times 1.21=87.12$

Total cost = 67.76+87.12=154.88

Hence It costs $154.88 to build the fences.

7 0

2 years ago

What are some different ways you could rewrite 32.y using the commutative property of multiplication

natulia [17]

Answer:

32y= 32(y) 32/1y 32xy

Step-by-step explanation:

6 0

2 years ago

Find the circumference of the sphere whose volume is 1375/21 cu. cm

Anit [1.1K]

Answer:

The circumference of the sphere is $C=5\pi\ cm$ or $C=15.7\ cm$

Step-by-step explanation:

step 1

Find the radius of the sphere

we know that the volume of the sphere is equal to

$V=\frac{4}{3}\pi r^{3}$

we have

$V=\frac{1,375}{21}\ cm^{3}$

substitute and solve for r

$\frac{1,375}{21}=\frac{4}{3}\pi r^{3}$

assume

$\pi =3.14$

$r^{3}=\frac{1,375}{21}(\frac{3}{4*3.14})$

$r=2.5\ cm$

step 2

Find the circumference

The circumference is equal to

$C=2\pi r$

we have

$r=2.5\ cm$

substitute

$C=2\pi(2.5)$

$C=5\pi\ cm$

assume

$\pi =3.14$

$C=5(3.14)=15.7\ cm$

8 0

2 years ago

Explain why 0.323232 is greater than 0.32

horrorfan [7]

Step-by-step explanation:

0.323232 is greater than 0.32 because numbers of value are many of firsts number

8 0

1 year ago

Read 2 more answers

!20 PTS!

FromTheMoon [43]

For both problems, we can use the section formula.

1) $Z=\left(\frac{(2)(7)+(1)(1)}{3}, \frac{((2)(5)+(1)(2)}{3} \right)=\boxed{(5, 4)}$

2) $P=\left(\frac{(1)(1)+(5)(-9)}{6}, \frac{(1)(8)+(5)(3)}{6} \right)=\boxed{\left(-\frac{22}{3}, \frac{23}{6} \right)}$

7 0

2 years ago