Sum of the angles of any quad =360
then y+(x+2)+(x-2)+(x-10) = y +3x -10 =360 (by adding both sides by 10)
y + 3x =370 ;.... eq 1
the sum of each two opposite sides in a quad inscribed in a circle =180
then (x+2)+(x-2)=180
therefore 2x =180
therefore x=90 (sub in eq 1)
y+3*90 =y +270 = 370 (subtracting both sides by 270)
therefore y=100
then measure angle B=100 degrees
A=92 degrees
C=88 degrees
D=80 degrees
Answer: 7) 50.27 8) 251.33 9) 235.62 *These answers were calculated using the true value of pi, not 3.14*
We know that
the area A of the circular cross section of the pipe is
A=pi*r²
D=20 cm------------- > r=D/2=20/2=10 cm
then
A=pi*10²=100*pi cm²
the answer is A=100*pi cm²
I think the equation that is not true is D. (200m = 2cm)
Hope this helps! :D
Area of shaded part = area of circle - area of the square
= pi (6)^2 - area of the square.
Area of square = (m of one side) ^2
measure of of side is found as follows:-
6^2 = 2s^2 where m of the side = 2s
s = sqrt 18 so side of square = 2 sqrt18
area of square = (2 sqrt18)^2 = 4*18 = 72
area of shaded region = 36pi - 72 = 41.1 sq units to neraest tenth
