Answer:
By hypotenuse - side test (HL) the two triangles are congruent.
Step-by-step explanation:
In ∆ABC and ∆DCB
i) angleABC = angleDCB.....(each 90°)
ii) BC = BC .....( common side)
iii) AC = DB.....(given)
 therefore by hypo-side test ∆ABC congruent ∆DCB
 
        
                    
             
        
        
        
Answer:
20 degfress
Step-by-step explanation:
 
        
             
        
        
        
If a = first term and r = common ratio we have
a + ar + ar^2 = 13   and ar^2 / a = r^2 = 9
so r = 3
and a + 3a + 9a = 13 
so a = 1
so they are  1,3 and 9 
2.
in geometric series we have
4 , 4r ,4r^2 , 60
Arithmetic;
 4,  4r , 4r + d ,  4r + 2d
so we have the system of equations 
4r + 2d = 60
4r^2 = 4r + d
From first equation
2r + d = 30 
so d = 30 - 2r 
Substitute for d in second equation:-
4r^2 - 4r - (30-2r) = 0
4r^2 - 2r - 30 =0
2r^2 - r - 15 = 0
(r - 3)(2r + 5) = 0
r  = 3 or -2.5
r must be positive so its = 3
and d = 30 - 2(3) = 24
and the numbers are 4*3 =  12 , 4*3^2 = 36
first 3  are  4 , 12 and 36  ( in geometric)
and last 3 are 12, 36 and 60  ( in arithmetic)
The 2 numbers we ause are 12 and 36.
        
             
        
        
        
Quadruple check is so cute and I love it soro much I love it solo much and